Answer:
The minimum sample size required is 207.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean <em>μ</em> is:

The margin of error of this confidence interval is:

Given:

*Use a <em>z</em>-table for the critical value.
Compute the value of <em>n</em> as follows:
![MOE=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=2.576\times \frac{29}{\sqrt{n}} \\n=[\frac{2.576\times29}{3} ]^{2}\\=206.69\\\approx207](https://tex.z-dn.net/?f=MOE%3Dz_%7B%5Calpha%20%2F2%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C3%3D2.576%5Ctimes%20%5Cfrac%7B29%7D%7B%5Csqrt%7Bn%7D%7D%20%5C%5Cn%3D%5B%5Cfrac%7B2.576%5Ctimes29%7D%7B3%7D%20%5D%5E%7B2%7D%5C%5C%3D206.69%5C%5C%5Capprox207)
Thus, the minimum sample size required is 207.
Answer:
Cant answer
Step-by-step explanation:
Depending on the option choices and without seeing the option choices I can give you an idea of how to solve this.
Using y=mx+b we can find the y intercept by knowing that B is the value of the y Intercept
Answer:
25%
Step-by-step explanation:
From the boxplot Given, an earning of $25 or less is represented on the boxplot as the lower quartile of the distribution which is the point at the start of the box. The lower quartile value is the percentage value up to 25% that is the first 25% of the distribution.
Hence, the percentage required = 25%
Hence, Nicholas earned $25 or less about 25% of the time.
If

and

are <span>supplementary angles, then

The ratio of

and

is

<span>

Substitute

into


From

we find the measure of


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