Put the argument value where the variable is, then evaluate.
For f(x), you want f(2).
f(2) = 2² + 1 = 4+1 = 5
For g(x), you want g(1).
g(1) = 3·1 +1 = 4
For [f(2) - g(1)] you want the difference of the above values.
[f(2) - g(1)] = [5 - 4] = 1
Answer:
3y
Step-by-step explanation:
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Algebra
Factor
Factor the polynomial.
(
x
+
3
)
(
x
+
5
)
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()|[]ó
789≤
456/^×>∩∪
123-+÷<π∞
,0.%=
Factor
x
2
+
8
x
+
15
+
0
Regroup terms.
x
2
+
0
+
8
x
+
15
Add
x
2
and
0
.
x
2
+
8
x
+
15
Factor
x
2
+
8
x
+
15
using the AC method.
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Consider the form
x
2
+
b
x
+
c
. Find a pair of integers whose product is
c
and whose sum is
b
. In this case, whose product is
15
and whose sum is
8
.
3
,
5
Write the factored form using these integers.
(
x
+
3
)
(
x
+
5
)
