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Zarrin [17]
3 years ago
15

Which of the following materials could have been found in the giant cloud that formed the solar system?

Physics
2 answers:
iren2701 [21]3 years ago
6 0
Liquid and solid water were not in the giant gas cloudr
Brilliant_brown [7]3 years ago
4 0
3. Carbon dioxide and oxygen

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Which of the moon’s properties prevents it from being pulled inward by earth?
bekas [8.4K]

Answer:

Inertia

Explanation:

Inertia is the inherent property of an object to remain in its state of rest or motion without being disturbed.

6 0
4 years ago
Read 2 more answers
An is holding an ice cube. What causes the ice to melt?
ivann1987 [24]

Answer: A... Thermal energy from the ice is transferred to the air.

Explanation: because I just know.

6 0
3 years ago
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
Anton [14]

Answer:

91.64 km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

Explanation:

According to Newton Law of gravitation:

g=\frac{Gm}{r^2}

Where:

G is gravitational constant=6.67*10^{-11} m^3/kg.s^2

For Moon lo g is:

g_M=\frac{6.67*10^{-11}*8.93*10^{22}}{(1821*10^3)^2m^2} \\g_M=1.7962 m/s^2

According to law of conservation of energy

Initial Energy=Final Energy

K.E_i+mgh_i=K.E_f+mgh_f

\frac{1}{2}m(v_0)^2+mgh_o= \frac{1}{2}m(v_f)^2+mgh_f\\At\ maximum\ height\ v_f=0\\\frac{1}{2}m(v_0)^2+0=mgh_f\\v_0=\sqrt{2gh_f}

For Jupiter's moon Io:

Velocity is given by:

v_0_M=\sqrt{2g_Mh_f_M}

For Earth Velocity is given by:

v_0_E=\sqrt{2g_Eh_f_E}

Now:

v_o_M=v_o_E

\sqrt{2g_Mh_f_M}=\sqrt{2g_Eh_f_E}\\h_f_E=\frac{g_Mh_f_M}{g_E}

g_E=9.8 m/s^2

g_m=1.7962 m/s^2, As\ Calculated\ above

h_f_E=\frac{1.7962*500*10^3m}{9.8} \\h_f_E=91642.85 m\\h_f_E=91.64Km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

8 0
4 years ago
If you walk at an average speed of 5 km/h for 30 minutes, how
timurjin [86]
Time= s/v

Speed =5km/h
Time=30min
Distance is required
Distance=time*speed
30min*5km/h=600m
4 0
3 years ago
A train reaches a speed of 35.0 m/s after accelerating at a rate of 5.00 m/s2 over a distance of 40.0 m. What was the train’s in
MatroZZZ [7]

Answer:

Initial velocity, U = 28.73m/s

Explanation:

Given the following data;

Final velocity, V = 35m/s

Acceleration, a = 5m/s²

Distance, S = 40m

To find the initial velocity (U), we would use the third equation of motion.

V² = U² + 2aS

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

S represents the displacement measured in meters.

Substituting into the equation, we have;

35² = U + 2*5*40

1225 = U² + 400

U² = 1225 - 400

U² = 825

Taking the square root of both sides, we have;

Initial velocity, U = 28.73m/s

5 0
3 years ago
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