The current initially through the fingers is : 1.5 * 10⁻⁵ amp
The current when the resistance between them drops is : 3 * 10⁻⁵ amp
<u>Given data : </u>
Voltage ( V ) = 6 V
Initial resistance ( r ) = 400,000 ohms
Final resistance ( R ) = 200,000 ohms
<h3>Determine The Current </h3>
A) initially through fingers
I = V / r
= 6 V / 400,000
= 1.5 * 10⁻⁵ amp
B) when the resistance between them drops
I = V / R
= 6 V / 200000
= 3 * 10⁻⁵ amp
Hence we can conclude that The current initially through the fingers is : 1.5 * 10⁻⁵ amp and The current when the resistance between them drops is : 3 * 10⁻⁵ amp
Learn more about current calculation : brainly.com/question/25922783
I) Tension in the spring = 2N
ii) Angular speed of the bung=5 rads-¹
iii) The time(T) it takes to make one complete revolution=1.256 seconds
<h3>Circular motion</h3>
Formula used to calculate the time(T) it takes to make one complete revolution = 2π √(l/g)
l = radius= 40cm = 0.4m
g = acceleration due to gravity = 10m/s-²
π =3.14( constant)
T = 2× 3.14 × √0.4/10
T = 6.28 ×√0.04
T = 6.28 × 0.2
T= 1.256 seconds
Formula to calculate angular speed(w)= 2π/T
where T= 1.256 secs
Therefore w = 2×3.14/1.256
w = 6.28/ 1.256
w = 5 rads-¹
Formula to calculate Tension in the spring(F)
= mrw²
where m= 200 g = 0.2kg
r = radius= 40cm = 0.4m
w = angular speed = 5 rads-¹
Therefore F = 0.2 × 0.4 × 5²
= 0.08 ×25
= 2N
Learn more about angular speed here:
brainly.com/question/6860269
In order to find out if the exponential function represents a growth or a decay, let's look at the number that is base to the exponent x.
If the number is greater than 1, so the function represents a growth, and if the number is less than 1, the function represents a decay.
Since the number is 1.075, the function represents a growth.
To find the % increase, first let's convert the number to percentage, and then subtract 100%:
So the percent increase is 7.5%.
Answer:
a) v = 0.7071 v₀, b) v= v₀, c) v = 0.577 v₀, d) v = 1.41 v₀, e) v = 0.447 v₀
Explanation:
The speed of a wave along an eta string given by the expression
v =
where T is the tension of the string and μ is linear density
a) the mass of the cable is double
m = 2m₀
let's find the new linear density
μ = m / l
iinitial density
μ₀ = m₀ / l
final density
μ = 2m₀ / lo
μ = 2 μ₀
we substitute in the equation for the velocity
initial v₀ =
with the new dough
v =
v = 1 /√2 \sqrt{ \frac{T_o}{ \mu_o} }
v = 1 /√2 v₀
v = 0.7071 v₀
b) we double the length of the cable
If the cable also increases its mass, the relationship is maintained
μ = μ₀
in this case the speed does not change
c) the cable l = l₀ and m = 3m₀
we look for the density
μ = 3m₀ / l₀
μ = 3 m₀/l₀
μ = 3 μ₀
v =
v = 1 /√3 v₀
v = 0.577 v₀
d) l = 2l₀
μ = m₀ / 2l₀
μ = μ₀/ 2
v =
v = √2 v₀
v = 1.41 v₀
e) m = 10m₀ and l = 2l₀
we look for the density
μ = 10 m₀/2l₀
μ = 5 μ₀
we look for speed
v =
v = 1 /√5 v₀
v = 0.447 v₀
Answer:
3 hours 71 minutes
Explanation:
As because Speed= distance/time taken
so time taken= 3.71