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Alenkinab [10]
3 years ago
12

What is the relationship between the line current i l and the phase current i1 in a balanced delta system?

Physics
1 answer:
Natasha_Volkova [10]3 years ago
6 0
<span>In a star connection the line current is equal to the phase current . While in Delta connection  the line current is divided by under root 3 to get the phase current.</span>
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with what speed does a freely falling object dropped from a height of 88.2m hit the ground? how long does it take for it hit the
Kryger [21]

Answer:

Vf = 41.6 [m/s].

Explanation:

To solve this problem we must use the equations of kinematics.

Vf² = Vo² + (2*g*y)

where:

Vf =  final velocity [m/s]

Vo = initial velocity = 0

g = gravity acceleration = 9.81 [m/s²]

y = height = 88.2 [m]

Note: The positive sign of the equation tells us that the acceleration of gravity goes in the direction of motion.

Vf² = Vo² + (2*g*y)

Vf² = 0 + (2*9.81*88.2)

Vf = (1730.48)^0.5

Vf = 41.6 [m/s]

6 0
3 years ago
A small compass is placed near a current-carrying wire. The wire is vertical, and the compass is on a horizontal surface. The re
azamat

Answer:

The direction of magnetic field produced by a current carrying wire is given by the right hand thumb rule. If the thumb points in the direction of current the fingers curl along the direction of magnetic field.

further, The red end of the compass needle points in the direction of external magnetic field. As the red end of the needle is pointing away from us, the external magnetic field at its location should also be directed away from us. Using the right hand thumb rule, we can see that this is only possible if the current in the wire is flowing upwards.

Explanation:

5 0
4 years ago
A car of mass 900 kg is traveling at 20 m/s when the brakes are applied. The car then comes to a complete stop in 5 s. What is t
ollegr [7]

Answer:

A. 36,000 W

Explanation:

m = mass of the car = 900 kg

v_{o} = Initial speed of the car = 20 m/s

v_{f} = Final speed of the car = 0 m/s

W = Work done by the brakes on the car

Magnitude of work done on the car by the brakes is same as the change in kinetic energy of the car.hence

W = (0.5) m (v_{o}^{2} - v_{f}^{2})\\W = (0.5) (900) ((20)^{2} - (0)^{2})\\W = 180000 J

t = time taken by the car to come to stop = 5 s

P = Average power produced by the car

Average power produced by the car is given as

P = \frac{W}{t} =\frac{180000}{5} \\P = 36000 W

8 0
3 years ago
You are trying to push a 30 kg canoe across a beach to get it to a lake. Initially, the canoe is
Akimi4 [234]

Answer:

m = 30, g = 9.8, coefficient = 0.2, so force due to friction = 30 x 9.8 x 0.2 = 58.8 N, so work done by friction = 58.8 x 1.2 = 70.56 J

Explanation:

8 0
3 years ago
Playing a game of soccer, baseball or basketball change if inertia ended?
Fittoniya [83]
Soccer.hope this helps! brainiest please!
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