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3 years ago

What is 1/2 times 5/2

Mathematics

2 answers:

Elena L [17]3 years ago

7 0

Answer:

1/2 x 1/5 is .1

Step-by-step explanation:

Artemon [7]3 years ago

6 0

Answer:

= 5/4

Step-by-step explanation:

Multiply across, so we will multiply our numerators first.

1 x 5 = 5

Then we multiply our denominators

2 x 2 = 4

Thats why your answer is 5/4

Hope this helps (:

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A) A pack of 8 batteries cost £3.99 how much dose each battery cost? ( give your answer in penny ?) ____________________________

just olya [345]

Answer:

A). 50 penny

B) This type of battery is cost effective.

Step-by-step explanation:

A) A pack of 8 batteries cost 3.99 pounds so one battery will cost = 3.99/8 = 0.499 pound

Since 1 pound = 100 penny

So 0.499 pound = 100×0.499 = 50 penny

B). A pack of 6 batteries of the same type costs 2.79 pounds

So one battery will cost = 2.79/6 = 0.465 pound or 47 penny

Now we say that type A batteries are costlier than B. Therefore B type batteries are of a better value.

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2 years ago

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James earns 20 allowance every month and 30 for each a on his report card

Svetach [21]

Answer:

Part A - the independant variable is the monthly allowance, and the dependent amount is the one that he has to get As for in order to receive it.

Part B - y = 30x + 20

Step-by-step explanation:

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2 years ago

Picture attachment is below

Stolb23 [73]

Answer:

Step-by-step explanation:

A rational number will either end or repeat forever like the first three, but the fourth one, pi, will go on forever and never repeat, making it irrational.

5 0

2 years ago

What is the average rate of change of the function over the interval x = 0 to x = 8?

Hatshy [7]

Answer:

if f(x) = 3x+4, the rate of change is 4.

if f(x) = 2x+7, the rate of change is 2.

Step-by-step explanation:

We know that the average rate of change over the interval x=0 to x=8 is:

(f(x2) - f(x1))/x2-x1

Where:

x2 = 8

x1 = 0

if f(x) = 3x+4

so f(8)=3(8)+4 = 28

f(0)=3(0)+4 = 4

Then: (f(x2) - f(x1))/x2-x1 = (28 - 4)/8-0 = 24/8 = 3

On the other hand, if f(x) = 2x+7

f(8) = 2(8)+7 = 23

f(0) = 2(0)+7 = 7

Then: (f(x2) - f(x1))/x2-x1 = Then: 23 - 7/8-0 = 16/8 = 2

8 0

2 years ago

Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
g(x) = x^2-1

Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

7 0

1 year ago