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mars1129 [50]
2 years ago
5

Which inequality is represented by this graph

Mathematics
1 answer:
Nuetrik [128]2 years ago
4 0
The line is solid and under the line is shaded
so the answer is A
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Joe is going for a walk. He walks at a speed of 3 miles per hour for 7.5 miles. For how many hours does he walk?
Ksju [112]
Answer: 2.5 hours
explanation:
7.5/3=2.5
6 0
3 years ago
What is 7 less than y<br> In math
saw5 [17]

Answer:

The algebraic expression is "y - 7".

Step-by-step explanation:

"7 less" means "- 7", so you're subtracting 7 from y. You then write it as "y - 7".

5 0
2 years ago
Read 2 more answers
A bicyclist slow with a force of 3.5 × 10² N. if the bicyclist and bicycle have a total mass of 1.0 × 10² kg, what is the accele
Aleonysh [2.5K]

Answer:

3.5 m/s²

Step-by-step explanation:

We are given;

  • The force of a bicycle as 3.5 × 10² N
  • Mass of the bicycle as  1.0 × 10² kg

We are required to determine the acceleration of the bicycle;

From Newton's second law of motion;

F = ma

Rearranging this;

a = F÷ m

Therefore;

Acceleration = 3.5 × 10² N ÷ 1.0 × 10² kg

                     = 3.5 m/s²

Thus, the acceleration of the bicycle is 3.5 m/s²

7 0
3 years ago
Avery paid a $5.00 entrance fee to the carnival
Anna007 [38]
Let’s start off by subtracting 5 from 10 leaving 5 dollars

if 6 tickets cost 3 dollars she can only buy 6 tickets because she will only have 2 dollars left
3 0
3 years ago
I have the first part but I don't know how to do the second part<br><br> h e l p
Debora [2.8K]

\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42

3 0
2 years ago
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