Answer:
Advantages:
Low Level Irradiation kills bacteria and parasites.
The Nutrition value of of irradiated food is the same as regular food with less bacteria.
Irradiation makes fruits and vegetables riper and spoil slower.
Disadvantages:
Irradiation will increase cost of food.
The percentage of radiation as always being negative will also make
Irradiated food are not widely available yet.
Complete question:
1). Determine the character states for the following six characters that are present in species OG, 5, 7, 15, 17, 18. Assign the character state found in the outgroup (OG) as a 0 and the alternative derived state a 1; use only two states per character. Example, stem width: 0 = thin, / = thick 1 <em>(Characters and plant species image in the attached files)</em>
2). Score each taxon using the 0 and 1 notation about and add to this matrix <em>(Matrix in the attached files)</em>
4). Reconstruct the phylogeny that most simply and accurately accounts for the distribution of synapomorphies among ingroup species. Given matrices as small and simple as the above example, one can build the tree from the bottom up in a series of sketches, adding clades or branches representing groups with the fewest synapomorphies near the base of the tree and those with the most at the tips. Using the unlabeled phylogeny as a starting point, draw the stepwise construction of a fully resolved phylogeny to account for all of the synapomorphies and include the synapomorphies that identify each clade (the first one, character 2, is included to get you started; this is shared by all members of the ingroup) (<em>Tree in the attached files)</em>
Answer:
- Stem width: Thick-1 // Thin-0
- Leaf edge (shape): Pointed-1 // Blunt-0
- Flower base (shape): Narrow-0 // Wide-1
- Flower orientation: Downward (Pendant)-1 // Upward (Vertical)-0
- Petal color: Purple-1 // Yellow-0
- Fruit shape (inset on card, on left): Round-0 // Elongated-1
- Complete Matrix in the attached files
- Order in the phylogeny reconstruction: OG --> 7 --> 5 --> 15 --> 17 and 18 (tree + evolutive changes in the attached files)
Explanation:
<em>NOTE: You will find the complete activity in the attached files. </em>
- The principle of maximum parsimony or maximum simplicity states that among all possible trees within a group of species, the most probable is the one that requires us to postulate the least number of evolutionary changes. So, to reconstruct a phylogeny we need to choose the tree that requires the less number of changes.
- To determine the character states for all the six characters, we assigned the number cero to all the characters expressed in the out-group. Thin steam, blunt leaf, narrow flower base, upward flower orientation, yellow petals, and rounded-seeds are all cero states. The other characters are 1.
- The above information of character state was used to fill in the matrix, specifying which character state belongs to each species according to their traits.
- The matrix was useful to reconstruct the phylogeny, to identify the autapomorphic trait, and to visualize all the clades.
Answer:
Corbin recently found out that he has cancer, and he now strictly follows a treatment, diet, and exercise program that the doctor thinks will be helpful in keeping the cancer from spreading. These behaviors best illustrate <u>problem-focused</u> coping.
Explanation:
Problem-focused coping seeks to tackle the stressor head-on allowing the individual greater perceived control over their problem resulting in :
- Managing and changing the stressor
- Use if problem seems alterable
- Confrontice coping
- Planful problem solving
As Cobbin is strictly following treatment, diet and exercise programs that the doctor thinks will be helpful in keeping the cancer from spreading, Cobbin is showing <u>problem-focused coping.</u>
Carbon is found in the atmosphere mostly as carbon dioxide.
Answer:
The correct answer is -
1. right-handed
2. right-handed
3. positive
4. left-handed
5. negative
6. negative
Explanation:
In a circular bacterial chromosome, the structure of DNA is a right-handed double helix In a circular bacterial chromosome.
If DNA is twisted in the right-handed direction, it becomes overwound. Overwinding results in positive supercoiling takes place. If DNA is twisted in the left handd direction, it becomes underwound. Underwinding results in negative supercoiling.
f. One effect negative supercoiling in bacterial chromosomes is to promote separation of the two strands of DNA in the double helix