Answer:
6ab(2a-3b-5b²)
Step-by-step explanation:
6(2a²b-3ab²-5ab³)
6a(2ab-3b²-5b³)
6ab(2a-3b-5b²)
Answer:
I think it's prove the midpoints are the same
Step-by-step explanation:
I'm not completely sure but I'm taking it right now and I believe that's the most logical answer because if they meet up at the same midpoint then they could bisect each other.
So hmmm x²+6x+8=0
alrite.. let's do some grouping now
( x² + 6x + [?]²) + 8 = 0
notice above, we have a missing fellow in order to get a perfect square trinomial... hmm who would that be?
let's take a peek at the middle guy of the trinomial.. 6x.. hmmm let's factor it, 2*3*x, wait a minute! 2 * 3 * x... we already have x² on the left-side, since the middle term is just 2 * the square root of the other two terms, that means that the guy on the right, our missing guy must be "3"
alrite, let's add 3² then, however, bear in mind that, all we're doing is borrowing from our very good friend Mr Zero, 0
so if we add 3², we also have to subtract 3², let's do so
(x² + 6x +3² - 3²) + 8 = 0
(x² + 6x +3²) + 8 - 3² = 0
(x+3)²=3² - 8
(x+3)² = 1
Answer: 49
Step-by-step explanation:
a=1 ,b=14, c=?
b^2-4ac =0
(14)^2-4(1)(c)=0
196-4c=0
196=4c
c=49
Check:
(x)^2+2(x)(7)+(7)^2
x^2+14x+49
(x+7)^2
