All categories

3 years ago

Are the three angles in a triangle complementary,supplementary,or neither

Mathematics

2 answers:

lawyer [7]3 years ago

8 0

Supplementary because it's just like complementary angles except supplementary adds up to 180 degrees. Often you will see supplementary angles created in a ray shoots out from a flat line. For example

Leviafan [203]3 years ago

3 0

They are all supplementary to each other because supplementary means that they all add up to 180

You might be interested in

What is the answer? 5(6x-2) = -250

faust18 [17]

Answer:

x = -8

Step-by-step explanation:

5(6x-2) = -250

30x - 10 = -250

30x/(30) = -240/(30)

x = -8

4 0

3 years ago

Read 2 more answers

A travel agent is booking trips for tourists who travel from New York to Chicago. Tourists have three choices for how to travel

Hitman42 [59]

List all the different combinations with total cost:

Airplane + van = 350 + 60 = $410

Airplane + cab = 350 + 40 = $390

Bus + van = 150 + 60 = $210

Bus + cab = 150 + 40 = $190

Train + van = 225 + 60 = $285

Train + cab = 225 + 40 = $265

There are 6 different combinations.

There are 2 that are more than $300

The probability would be quantity higher than 300 / total combinations.

Probability = 2/6 = 1/3

4 0

2 years ago

How many significant digits are in 1000.10? c. 5 b. 3 d. 6 a. 2

Y_Kistochka [10]

6 significant digits (D)

5 0

2 years ago

Read 2 more answers

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

3 years ago

2x3x4x5x6x7x9x10x20x31x41x42

dalvyx [7]

Step-by-step explanation:

$2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 9 \times 10 \times 20 \times 31 \times 41 \times 42 \\ 6 \times 20 \times 42 \times 90 \times 620 \times 1722 \\ 120 \times 3780 \times 1,067,640 \\ 453,600 \times 1067640 \\ = 4.84281504 \times {10}^{11}$

8 0

3 years ago

Read 2 more answers