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2 years ago

The value of y varies directly with x. When y = 25, x = 6 1/4. What is the value of y when x is 12? 4

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

6 0

Answer:

Step-by-step explanation:

if y = 25 when x = 6 1/4, then when y = 12, that would mean that we divided 25 by 2.0833. So we can do 6 1/4 divided by 2.0833 is the answer which is 3.00004800077.

(i think)

(probably wrong)

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Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$ are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. $\vec{A}\cdot \vec{B}=0$

Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$

$(i+j+kq)\cdot (iq-2j+2kq)=0$

$(1)(q)+(1)(-2)+(q)(2q)=0$

$q-2+2q^2=0$

$2q^2+q-2=0$

Using quadratic formula,

$q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}$

$q=\frac{-1\pm\sqrt{17}}{4}$

$q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}$

$q=0.781,-1.281$

Therefore, The value of q are 0.781,-1.281.

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