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Juliette [100K]
2 years ago
7

. Consider the following standards.

Mathematics
2 answers:
Slav-nsk [51]2 years ago
8 0
The answer is C, i did this
iris [78.8K]2 years ago
7 0

Part A:

A combined function is defined by <u>combining</u> with existing functions using addition, subtraction, multiplication or division.

A composite function is created by plugging one function <u>into</u> another.

Part B:

The class is selling sweaters an. the cost of each sweater is 8 dollars. There is a fee to create the design. The class plans to sell the sweaters for 12 dollars.

Part C:

Amy works at a baked goods store. She receivers a weekly salary of 350 dollars and is payed 3 percent commission on weekly sales over 1,500 dollars.

oof that took a while lol

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If you could help I would really appreciate it, but if not that’s fine. Thank you.
Kobotan [32]
Since 7 is greater than 5, you input it into the last equation.

2•(7) -7
14-7
7

The answer is 7!
3 0
2 years ago
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
Please answer this correctly as soon as possible I want genius or expert people to answer this correctly
Ede4ka [16]
6/54 times because there are 9 marbles and the orange marble is 1 out of those 9 marbles. If you multiply 6*9= 54 then you notice there is a 6/54 chance of picking any 1 marble out of the 54 times that you decide to pick marbles.
4 0
3 years ago
What is the value of 9/10÷1/5 ?
Anna35 [415]
The answer of 9/10 divided by 1/5 is 4.5
3 0
3 years ago
Read 2 more answers
The mathematics department of a college has 6 male professors, 9 female professors, 5 male teaching assistants, and 6 female tea
Hitman42 [59]

Given:

6 male professores

9 female professores

5 male teaching assistants

6 female teaching assistants

Sol:.

N(A\text{ or B)=N(A)+N(B)-N(A and B)}

N (professors)

\begin{gathered} =6+9 \\ =15 \end{gathered}

N(Male)

\begin{gathered} =6+5 \\ =11 \end{gathered}

N(professors and male)

=6

N(professors OR male) = N(professors) + N(males) -N(professor OR male)

\begin{gathered} N(\text{ Professors OR male)=15+11-6} \\ =20 \end{gathered}

N(People to choose from)

\begin{gathered} =6+9+5+6 \\ =26 \end{gathered}

Then probablitiy is:

\begin{gathered} =\frac{20}{26} \\ =\frac{10}{13} \end{gathered}

Then the probability is 10/13

6 0
1 year ago
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