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3 years ago

. Consider the following standards.

Mathematics

2 answers:

Slav-nsk [51]3 years ago

8 0

The answer is C, i did this

iris [78.8K]3 years ago

7 0

Part A:

A combined function is defined by <u>combining</u> with existing functions using addition, subtraction, multiplication or division.

A composite function is created by plugging one function <u>into</u> another.

Part B:

The class is selling sweaters an. the cost of each sweater is 8 dollars. There is a fee to create the design. The class plans to sell the sweaters for 12 dollars.

Part C:

Amy works at a baked goods store. She receivers a weekly salary of 350 dollars and is payed 3 percent commission on weekly sales over 1,500 dollars.

oof that took a while lol

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Find the value of c so that (x-5) is a factor of the polynomial p(x)

liubo4ka [24]

I think the question is

Find the value of c so that (x-5) is a factor of the polynomial

$p(x) = x^3 + 2x^2 + cx + 10$

The other factor is going to be some quadratic. We can say a few things about its coefficients but let's start by saying in general it's

$q(x)= ax^2 + bx + k$

$p(x) = (x-5)q(x)$

$x^3 + 2x^2 + cx + 10 = (x-5)(ax^2 + bx+k) = ax^3 + (b-5a)x^2 + (k-5b)x - 5k$

Equating respective coefficients,

$a=1$

$b-5a = 2$

$k - 5b = c$

$-5k = 10$

so we get

$b = 2 + 5 = 7$

$k = 10/-5 = -2$

$c = k - 5b = 2 - 5(7)= -37$

Answer: -37

Check:

$(x^2 + 7x - 2)(x - 5) = x^3 + 2 x^2 - 37 x + 10\quad\checkmark$

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3 years ago

What is the answer to x/3 - 2 < 8

balu736 [363]

Step-by-step explanation:

$\frac{x}{3} - 2 < 8 \\ \frac{x}{3} < 10 \\ x < 30$

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3 years ago

Quadrilateral RSTU has vertices R(1,3), S(4,1), T(1,-3) and U(-2,-1). Is it true or false that this is a rectangle because the d

Alex777 [14]

Given vertices ofQuadrilateral RSTU as R(1,3), S(4,1), T(1,-3) and U(-2,-1).

We need to check if diagonals are congruent.

The coordinates of verticales diagonal RT are R(1,3) and T(1,-3).

The coordinates of verticales diagonal SU are S(4,1), and U(-2,-1),

By applying distance formula:

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$