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Setler79 [48]
3 years ago
13

A horse pulls a sled 100 meters. The horse applies 200 newtons of force. How many joules of work did the horse do?

Physics
1 answer:
MAXImum [283]3 years ago
7 0

Explanation:

work done = force × distance

= 200N × 100m

= 20000J

= 20KJ

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A thin film of oil of thickness t is floating on water. The oil has index of refraction no = 1.4. There is air above the oil. Wh
vesna_86 [32]

Answer:t=0.1205

Explanation:

Given

Refractive index of oil\left ( \mu \right )=1.4

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Condition for constructive interference is

2\mu _{oil}t=\frac{m\lambda }{2}

t=\frac{m\lambda }{4\mu _{oil}}

For m= 1 i.e. for minimum thickness

t=\frac{1\times 675\times 10^{-9}}{4\times 1.4}

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5 0
3 years ago
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alexandr402 [8]

Answer:

0.699 L of the fluid will overflow

Explanation:

We know that the change in volume ΔV = V₀β(T₂ - T₁) where V₀ = volume of radiator = 21.1 L, β = coefficient of volume expansion of fluid = 400 × 10⁻⁶/°C

and T₁ = initial temperature of radiator = 12.2°C and T₂ = final temperature of radiator = 95.0°C

Substituting these values into the equation, we have

ΔV = V₀β(T₂ - T₁)

= 21.1 L × 400 × 10⁻⁶/°C × (95.0°C - 12.2°C)

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6 0
3 years ago
Betelgeuse is 100,000 times more luminous than our sun, which means that it releases an estimated 3.846 x 1031 W of luminous lig
denis-greek [22]

Answer:

5.4  × 10⁸ W/m²

Explanation:

Given that:

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half the distance (i.e radius r ) = 7.5  × 10¹⁰ m

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The Intensity of  Betelgeuse  can be determined by using the formula:

Intensity \ I = \frac{P}{4 \pi r^2}

I = \frac{3.846*10^{31}}{4 \pi (7.5*10^{10})^2}

I = 544097698.8 W/m²

I = 5.4  × 10⁸ W/m²

8 0
3 years ago
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adoni [48]

Answer: Some jokes make no sense tbh

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3 years ago
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pantera1 [17]

Answer:

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0 °C = 273 K

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3 years ago
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