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Nitella [24]
3 years ago
10

What is pitch related to in terms of sound? Does it affect the speed? If so, how?

Physics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Pitch is the impression the listener gets of the <em>frequency</em> of the sound.

The speed of the sound is <em>not</em> related to its pitch/frequency.  

If the speed and frequency were related, that would be a real problem.  Bands, orchestras, and choirs could not exist !  All the instruments in the orchestra could play a note together, at the same time.  But then the higher instruments ... the flute, trumpet, violins, high guitar strings and high piano keys ... would travel to you fast, and the lower instruments ... the trombone, tuba, double bass, bass drum, low guitar strings and the low piano keys ... would travel to you slow.  They all played the note at the same time, but by the time you heard it, it would be all smeared out ... every instrument arriving at your ear at a different time !

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What is a distraction that a pedestrian may engage in while crossing the street?
goldenfox [79]

Answer:

a dog walking or their phone rings or heard a neighbor talking to them

6 0
3 years ago
n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f
pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0
3 years ago
Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. What is the truck’s velocity?
gladu [14]

<u>Answer:</u>

The velocity of the truck is 34 m/s.

<u>Explanation:</u>

The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:

<em>p = mv</em>

Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.

So substituting the given values in the above formula to find the velocity of the truck.

Truck's velocity = \frac{40120}{1180} = 34 m/s.

3 0
3 years ago
If temperature and the number of particles remain constant, and increase in pressure will cause volume to
omeli [17]
The correct answer is remain the same because if the particles and temperature remain constant, when the pressure increases the temperature is not increasing so it would just stay the same
5 0
3 years ago
According to the ideal gas law, increasing the volume of a closed reaction container decreases the thermal energy because the
viva [34]
B is ur answer the temputer does increase
4 0
3 years ago
Read 2 more answers
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