Answer:
V = 4.826m/s, 716N
Explanation:
At the lowest swinging point, the net force acting on the child is equal to the centripetal force and it could be represented as
F = mv^2/r
2T-mg =mv^2/r
r(2T-mg) = mv^2
Divide both sides by m
r(2T-mg)/m = mv^2/m
r(2T/m-g) = v^2
V= √ r(2T/m-g)
Where v is the velocity
r is the length of the chain
m is the mass of the child in kg
T is the tension in Newton
g is the acceleration due to gravity
Given that g = 9.8m/s^2
T = 358N
m = 41.0kg
r = 3.04m
Substituting the values into the formula
V = √ 3.04( 2*358/41 -9.89
V = √ 3.04 ( 716/41 - 9.8 )
V = √3.04 ( 17.463-9.8 )
V = √3.04( 7.6634)
V = √23.2967
V = 4.826m/s
For the second part which is the tension in the two chains
N - m*g = m*(v^2 / r)
N - (41)*(9.81) = (41)*(4.826^2 / 3.04)
N - 402.21 = 41×7.66
N - 402.21 = 314.112
N = 402.21 + 314.112
N = 716.332 newton
Approximately = 716N
Or alternatively, since there are two chains holding the swing, of which each chain is acted upon by a 358N tension. Hence = 2T
2*358 = 716N
Answer:
F = 30 N Directed up
Explanation:
We can solve this problem using the momentum and momentum relationship.
I = ΔP
I = ∫ F dt
As we are asked for the average force, that leaves the integral, giving
I = F t
F t = m 
- m v₀
F = m (-v₀) / t
Note that, if you define the upward positive direction, the initial velocity is negative
Let's calculate
F = 0.15 (3.5 - (-6.5)) / 0.050
F = 30 N
Directed up
Answer:-
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Hope this help :)
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