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Ludmilka [50]
3 years ago
11

The relation of mass m, angular velocity o and radius of the circular path r of an object with the centripetal force is-

Physics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

Correct option not indicated

Explanation:

There are few mistakes in the question. The angular velocity ought to have been denoted with "ω" and not "o" (as also suggested in the options).

The formula to calculate a centripetal force (<em>F)</em><em> </em>is

<em>F</em> = mv²/r

Where m is mass, v is velocity and r is radius

where

While the formula to calculate a centrifugal force (F) is

<em>F </em>= mω²r

where m is mass, ω is angular velocity and r is radius of the circular path.

<u>From the above, it can be denoted that the relationship been referred to in the question is that of a centrifugal force and not centripetal force, thus the correct option should be</u> C.

NOTE: Centripetal force is the force required to keep an object moving in a circular path/motion and acts inward towards the centre of rotation while centrifugal force is the force felt by an object in circular motion which acts outward away from the centre of rotation.

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5. A boy rides his skateboard 50 meters (m) West. Then he turns around
Ann [662]

Answer:

-30 m

Explanation:

50-20 but the direction is going west so it’s negative

5 0
3 years ago
A negative charge of -0.550 m exerts an upward <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5868766e
almond37 [142]

Answer:

a. +10.9μC

b. 0.600N and downward

Explanation:

To determine the magnitude of the charge, we use the force rule that exist between two charges which us expressed as

F=(kq₁q₂)/r²

since q₁=-0.55μC and the force it applied on the charge above it is upward,we can conclude that the second charge is +ve, hence we calculate its magnitude as

q₂=Fr²/kq₁

q₂=(0.6N*0.3²)/(9*10⁹*0.55*10⁻⁶)

q₂=0.054/4950

q₂=1.09*10⁻⁵c

q₂=10.9μC.

Hence the second charge is +10.9μC

b. From the rule of charges which state that like charges repel and unlike charges attract, we can conclude that the two above charges will attract since they are unlike charges. Hence the direction of the force will be downward into the second charge and the magnitude of the force will remain the same as 0.600N

8 0
3 years ago
A 20×10⁹charge is moved between two points A andB that are 30mm apart and have an electric potential difference of 600v between
Alona [7]

Answer:

John Felix Anthony Cena is an American professional wrestler, actor, and television presenter. He is currently signed to WWE. Born and raised in West Newbury, Massachusetts, Cena moved to California in 1998 to pursue a career as a bodybuilder.

Explanation:

7 0
3 years ago
I was playing goalie in a soccer league and made a save. The ball was traveling at 14 m/s and has a mass of 0.45 kg. How muck ki
Zigmanuir [339]

Answer:

Kinetic energy = 44.1 J

Explanation:

Given:

Velocity of ball = 14 m/s

Mass of ball = 0.45 kg

Find:

Kinetic energy

Computation:

An item's kinetic energy is force it has as a result of its motion. It is the amount of work necessary to move a body of a known volume from rest to a specified velocity.

Ke = (1/2)(m)(v²)

Ke = (1/2)(0.45)(14²)

Ke = (1/2)(0.45)(196)

Kinetic energy = 44.1 J

6 0
3 years ago
A speeding car is pulling away from a police car. The police car is moving at 30 m/s. The radar gun in the police car emits an e
Gekata [30.6K]

Answer:

65.625 m/s

Explanation:

F=20\times 10^9 Hz

\Delta F=F_r-F_t=4750 Hz

c = Speed of light = 3×10⁸ m/s

Relative speed

v=\frac{\Delta F}{2F}\times c\\\Rightarrow v=\frac{4750}{2\times 20\times 10^9}\times 3\times 10^8\\\Rightarrow v=35.625\ m/s

Relative speed = 35.625 m/s

Velocity of speeder = Velocity of police car + Relative speed

⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s

∴ Velocity of speeder is 65.625 m/s

6 0
3 years ago
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