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Ludmilka [50]
3 years ago
11

The relation of mass m, angular velocity o and radius of the circular path r of an object with the centripetal force is-

Physics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

Correct option not indicated

Explanation:

There are few mistakes in the question. The angular velocity ought to have been denoted with "ω" and not "o" (as also suggested in the options).

The formula to calculate a centripetal force (<em>F)</em><em> </em>is

<em>F</em> = mv²/r

Where m is mass, v is velocity and r is radius

where

While the formula to calculate a centrifugal force (F) is

<em>F </em>= mω²r

where m is mass, ω is angular velocity and r is radius of the circular path.

<u>From the above, it can be denoted that the relationship been referred to in the question is that of a centrifugal force and not centripetal force, thus the correct option should be</u> C.

NOTE: Centripetal force is the force required to keep an object moving in a circular path/motion and acts inward towards the centre of rotation while centrifugal force is the force felt by an object in circular motion which acts outward away from the centre of rotation.

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A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A se
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Answer:

W_2=-12J

Explanation:

The work of force 2 will be given by the vectorial equation W_2=F_2.d. We know the value of F_1 and have information about its movement, which relates to the net force F=F_1+F_2.

About this movement we can obtain the acceleration using the equation v_f^2=v_i^2+2ad. Since it departs from rest we have a=\frac{v_f^2}{2d}.

And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have F_2=F-F_1=ma-F1=\frac{mv_f^2}{2d}-F_1

And we had the work done by force 2 as:

W_2=F_2.d=\frac{mv_f^2}{2}-F_1d

(The sign will be given algebraically since we take positive the direction to the right.)

With our values:

W_2=\frac{(10kg)(2m/s)^2}{2}-(8N)(4m)=-12J

<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>

<em>W_1+W_2=K_f-K_i=K_f=\frac{mv_f^2}{2}</em>

<em>Which leads us to the previous equation straightforwardly.</em>

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3 years ago
An electric circuit where electrons are free to flow
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Answer: Electron flow / Electric current

7 0
3 years ago
Breaking a pencil in half is an example of: options:
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Answer:

b

Explanation:

8 0
4 years ago
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Which color had shortest wavelength
IgorLugansk [536]

the color violet has the shortest wavelength!

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4 years ago
Pun zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que caminar hay un insta
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Answer:

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

Explanation:

Según la Física, comprendemos que la presión es igual a la fuerza dividida por área. En este caso, el peso de la persona dividida por área total de los tacos de los zapatos de golf suponiendo una distribución uniforme de la fuerza. Es decir:

\sigma = \frac{W}{n\cdot A_{T}} (Eq. 1)

Donde:

\sigma - Presión, medida en libras por pulgada cuadrada.

W - Peso de la persona, medida en libras.

n - Cantidad de tacos en los zapatos, adimensional.

A_{T} - Área del taco, medida en pulgadas cuadradas.

Si conocemos que W = 180\,lb, n = 20 y A_{T} = 0.01\,in^{2}, la presión es:

\sigma = \frac{180\,lb}{(20)\cdot (0.01\,in^{2})}

\sigma = 900\,psi

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

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