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3 years ago

The relation of mass m, angular velocity o and radius of the circular path r of an object with the centripetal force is-

Physics

1 answer:

k0ka [10]3 years ago

8 0

Answer:

Correct option not indicated

Explanation:

There are few mistakes in the question. The angular velocity ought to have been denoted with "ω" and not "o" (as also suggested in the options).

The formula to calculate a centripetal force (<em>F)</em><em> </em>is

<em>F</em> = mv²/r

Where m is mass, v is velocity and r is radius

where

While the formula to calculate a centrifugal force (F) is

<em>F </em>= mω²r

where m is mass, ω is angular velocity and r is radius of the circular path.

<u>From the above, it can be denoted that the relationship been referred to in the question is that of a centrifugal force and not centripetal force, thus the correct option should be</u> C.

NOTE: Centripetal force is the force required to keep an object moving in a circular path/motion and acts inward towards the centre of rotation while centrifugal force is the force felt by an object in circular motion which acts outward away from the centre of rotation.

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A bucket of water of mass 10 kg is pulled at constant velocity up to a platform 30 meters above the ground. This takes 10 minute

Rudik [331]

Answer:

W = 2352 J

Explanation:

Given that:

mass of the bucket, M = 10 kg

velocity of pulling the bucket, v = 3 $m.min^{-1}$

height of the platform, h = 30 m

time taken, t = 10 min

rate of loss of water-mass, m = $0.4 kg.min^{-1}$

Here, according to the given situation the bucket moves at the rate,

$v=3 m.min^{-1}$

The mass varies with the time as,

$M=(10-0.4t) kg$

Consider the time interval between t and t + ∆t. During this time the bucket moves a distance

∆x = 3∆t meters

So, during this interval change in work done,

∆W = m.g∆x

<u>For work calculation:</u>

$W=\int_{0}^{10} [(10-0.4t).g\times 3] dt$

$W= 3\times 9.8\times [10t-\frac{0.4t^{2}}{2}]^{10}_{0}$

$W= 2352 J$

5 0

3 years ago

Debbie places two shopping carts in a cart Corral. she pushes the first cart, which then pushes a second cart. what force is bei

Bingel [31]

When Debbie pushes the first cart she is using an applied force. An applied force is created when someone or something pushes another thing using, of course, an applied force. Now, when the second cart is being pushed by the first cart, this is also an applied force. You can tell because the first cart is being pushed using forced and this causes the second cart to be pushed using some of the force that is being transmitted to the first cart.

Debbie exerts applied force on the first cart. The first cart exert applied force on the second cart.

- Marlon Nunez

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3 years ago

The modern periodic table has______ groups. (Write your answer as a number.)

kobusy [5.1K]

It contains 18 groups

4 0

3 years ago

Read 2 more answers

A proton in a particle accelerator is traveling at a speed of 0.99c

Gwar [14]

A proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.

<h3>What is speed of proton?</h3>

The speed of a proton is the rate at which a proton is moving through a given space.

The given speed of the proton is 0.99c

where;

c is speed of light

<h3>What is speed of light?</h3>

The speed of light in vacuum, commonly denoted c, is a universal physical constant that is important in many areas of physics.

The value of speed of light in a vacuum is given as 3 x 10⁸ m/s.

The speed of the proton is calculated as follows;

v = 0.99 x 3 x 10⁸ m/s.

v = 2.97 x 10⁸ m/s.

Thus, a proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.

Learn more about speed of proton here: brainly.com/question/14663642

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8 0

1 year ago

The size of a balloon increases when the pressure inside it increases. The balloon gets bigger when it is left in the heat from

Masteriza [31]

Explanation:

This happens because the gas inside tend to expand because its temperature gets higher.

This is why the balloon that is put in a freezer for too long tend to gets smaller, because the gas temperature that is inside the balloon decreases.

(you can try it at home)

It is related to the temperature of the gas.

5 0

3 years ago