d = distance between the two point charges = 60 cm = 0.60 m
r = distance of the location of point "a" where the electric field is zero from charge 
between the two charges.
= magnitude of charge on one charge
= magnitude of charge on other charge
= 3
= Electric field by charge at point "a"
= Electric field by charge at point "a"
Electric field by charge at point "a" is given as
= k /r²
Electric field by charge at point "a" is given as
= k /(d-r)²
For the electric field to be zero at point "a"
=
k /(d-r)² = k /r²
/(d-r)² = 3 /r²
1/(0.60 - r)² = 3 /r²
r = 0.38 m
r = 38 cm
Answer:
63.8 V
Explanation:
We are given that
Potential difference,V=140 V
We know that
According to question
In series
Potential across 1.2 square cm=
Hence, the voltage across the 1.2 square cm wire=63.8 V
Answer:
Sjsjsnsnusjsbsbwhwjahahjaia
