The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
2 gigabytes of data
Step-by-step explanation:
Given
Amount Jason keeps per month = $68.90
Cost of flat per month = $60.50
Balance for data = 68.90-60.50
Balance for data = $8.40
If 1Gigabyte = $4
x = $8.40
Cross multiply
4x = 8.40
x = 8.40/2
x = 2.20
Hence Jason can only use 2 gigabytes of data while staying within his budget
If I remember correctly perpendicular means right angle so I do not think it could be reversed.
Answer:
a
Step-by-step explanation:
2*1/6 is 2/6, which is 1/3
