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2 years ago

Exam Instructions

Mathematics

1 answer:

MaRussiya [10]2 years ago

7 0

Answer:

The answer is b ( an=3(-2)n-1

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Evaluate the function

vova2212 [387]

-1 you change all the x values to -1 and then solve

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3 years ago

Find the greatest common factor of 10, 30 and 45

lawyer [7]

Answer:

The greatest common factor is 5.

Step-by-step explanation:

The prime factorisation of 10, 30 and 45 is,

10 = 2 × 5

30 = 2 × 3 × 5

45 = 3 × 3 × 5

The prime factor '5' is common in the factorisation of 10, 30 and 45

So, the greatest common factor of 10, 30 and 45 is 5.

5 0

3 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

3 years ago

How will adding the value 90 affect the mean and median of the data set 1, 5, 5, 6, 9, 10?

Soloha48 [4]

I believe the answer is B for this question

6 0

3 years ago

Read 2 more answers

Help, Perhaps? this one has me kinda stumped, i know its prob easy, im just not to big brain rn lol :Sweat_emoji:

Naddika [18.5K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers