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adoni [48]
3 years ago
10

Las capas del lecho marino del Mar Mediterráneo cuentan la historia de los cambios ambientales en el hoy desértico norte de Afri

ca desde hace 160.000 años, haciendo uso de la regla de tres simple y notación científica indicar a cuántas décadas corresponde este periodo de tiempo con procedimiento
Chemistry
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

160.000 años corresponde a 16.000 décadas.

Explanation:

Para resolver correctamente el ejercicio debemos plantear la regla de tres simple de la siguiente manera:

1 década equivale a 10 años; A cuantas decadas equivalen 160.000 años?

1 década→10 años

          x    ←160.000 años

Debemos multiplicar 160.000 por 1 y luego dividir entre 10 ;

x=(\frac{160.000x1}{10})=16.000 décadas; en notación científica sería 16x10^3.

Respuesta: 160.000 años corresponde a 16.000 décadas.

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How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide
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Answer:

\boxed{\text{2.00 mol}}

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r:      58.32

          Mg(OH)₂ + … ⟶ … + 2HOH

m/g:       58.3

(a) Moles of Mg(OH)₂

\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}

The reaction will form \boxed{\textbf{2.00 mol}} of water.

6 0
3 years ago
Which causes genetic variations and can result in different alleles
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3 years ago
A chef is going to use a mixture of two brands of italian dressing. the first brand contains 7% vinegar, and the second brand co
faust18 [17]

Answer is: 180 mL of 7% vinegar and 60 mL of 11% vinegar.

ω₁ = 7% ÷ 100% = 0.07.<span>
ω</span>₂ = 11% ÷ 100% = 0.11.<span>
ω</span>₃ = 8% ÷ 100% = 0.08.<span>
V</span>₁ = ?.

V₂ = ?.<span>
V</span>₃ = V₁ + V₂.
V₃ = 240 mL.

V₁ = 240 mL - V₂.<span>
ω</span>₁ · V₁ + ω₂ ·V₂ = ω₃ · V₃.

0.07 · (240 mL - V₂) + 0.11 · V₂ = 0.08 · 240 mL.

16.8 mL - 0.07V₂ + 0.11V₂ = 19.2 mL.

0.04V₂ = 2.4 mL.

V₂ = 2.4 mL ÷ 0.04.

V₂ = 60 mL.

V₁ = 240 mL - 60 mL.

V₁ = 180 mL.

7 0
4 years ago
CO is a primary pollutant. <br> a. True<br> b. False?
Y_Kistochka [10]
<h2>Answer : Option A) true</h2><h3>Explanation : </h3>

CO which is carbon monoxide is a primary pollutant for air pollution. As it contributes to the major proportion in the air pollutants amongst others. It has 48% percent of pollutants in comparison to other pollutants of air. The source of carbon monoxide is mainly from incomplete combustion of fuel  mostly from the older cars.

The rise in atmospheric CO results in fatigue, drowsiness and my also sometimes lead to death of the person exposed to it.

3 0
3 years ago
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