According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,
P</span>₁ / T₁ = P₂ / T₂ ----- (1)
Data Given;
P₁ = 1.5 atm
T₁ = 35 °C + 273 = 308 K
P₂ = ?
T₂ = 0 °C + 273 = 273 K
Solving Eq. 1 for P₂,
P₂ = P₁ T₂ / T₁
Putting values,
P₂ = (1.5 atm × 273 K) ÷ 308 K
P₂ = 1.32 atm
Result:
As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.
Given the equilibrium reaction: 2 A (aq) + 3 B (aq) <— —> 2 C (aq) + D (aq) and equilibrium concentrations of [A] = 0.60M, [B] = 0.30 M, [C] = 0.10 M and [D] = 0.50 M. The Kc value will be:
a. 1.9 c. 2.4 b. 0.15 d. 0.51
Answer . A
9.0532e-5 should be correct! hope this helps
