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Aleks [24]
4 years ago
13

Rasheed calculates that his chemical reaction should produce 4 moles of product, but when he does the experiment, he gets only 3

moles. What is his percent yield?
Chemistry
1 answer:
Brut [27]4 years ago
8 0

Answer:

The answer to your question is 75%

Explanation:

Data

Theoretical production = 4 moles

Experimental production = 3 moles

Percent yield = ?

Formula

Percent yield = \frac{Experimental production}{Theoretical production} x 100

Substitution

Percent yield = \frac{3}{4} x 100

Result

Percent yield = 75 %

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Answer is c photosynthesis
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Two balloons have a negative charge. What happens when they are brought near each other?
Salsk061 [2.6K]

Answer:

They will attract each other because opposite charges attract

Explanation:

7 0
4 years ago
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What rate of reaction can be measured in the dark by determining the amount of oxygen gas consumed in a period of time?
Hatshy [7]

The rate of reaction that can be measured in the dark by determining the amount of oxygen gas consumed in a period of time is the rate of respiration.

Why?

Plants can undergo two types of reactions involving oxygen:

  1. <u>Photosynthesis: </u>In this type of reaction, plants use energy from light to synthesize glucose. The chemical reaction for photosynthesis is: 6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂, and this reaction produces oxygen gas in the presence of light, that means that to measure the rate of photsynthesis, you'll need to measure the amount of oxgen gas <u>produced</u> in a period of time.
  2. <u>Respiration:</u> In this type of reaction, plants convert the energy stored in the chemical bonds of molecules such as glucose to obtain energy. The chemical reaction for respiration is: C₆H₁₂O + 6O₂ → 6H₂O + 6CO₂, since this reaction consumes oxygen gas in the dark, that means that to measure the rate of respiration, you'll need to measure the amount of oxygen gas <u>consumed</u> in a period of time.

Have a nice day!

7 0
4 years ago
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For the following reaction, 7.43 grams of methane (CH4) are allowed to react with 27.6 grams of carbon tetrachloride. methane (C
NikAS [45]

Answer:

30.4 grams of CH2Cl2 will be formed

Explanation:

Step 1: data given

Mass of methane = 7.43 grams

Molar mass of methane (CH4) = 16.04 g/mol

Mass of CCl4 = 27.6 grams

Molar mass of CCl4 = 153.82 g/mol

Step 2: The balanced equation

CH4 + CCl4 → 2CH2Cl2

Step 3: Calculate moles

Moles = mass / molar mass

Moles methane = mass methane / molar mass methane

Moles methane = 7.43 grams / 16.04 g/mol

Moles methane = 0.463 moles

Moles CCl4 = 27.6 grams / 153.82 g/mol

Moles CCl4 = 0.179 moles

Step 4: Calculate limiting reactant

For 1 mol CH4 we need 1 mol CCl4 to produce 2 moles CH2Cl2

CCl4 is the limiting reactant. It will completely be consumed. (0.179 moles). Ch4 is in excess. There will react 0.179 moles. There will remain 0.463 - 0.179 = 0.284 moles

Step 5: Calculate moles CH2Cl2

For 1 mol CH4 we need 1 mol CCl4 to produce 2 moles CH2Cl2

For 0.179 moles CCl4 we'll have 2*0.179 = 0.358 moles CH2Cl2

Step 6: Calculate mass CH2Cl2

Mass CH2Cl2 = 0.358 moles* 84.93 g/mol

Mass CH2Cl2 = 30.4 grams

30.4 grams of CH2Cl2 will be formed

3 0
4 years ago
If 150 G of war started burning 300 G of where as was left behind how many grams of CO2 gas is released
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Answer:

geruow0irghvn3p0unhie0ghik

Explanation:

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