Answer:- Molar mass of
.
Solution:- It is a stoichiometry problem. Mass of the grill is 30.0 kg and the mass after burning the grill is also 30.0 kg. It means all the charcol is burned and the gas is given off.
2.0 kg of charcol are converted to grams which is 2000 g. Since charcol is pure solid carbon, the grams are divided by the atomic mass of carbon which is 12.
The combustion equation of charcol is written as:

From this balanced equation, there is 1:1 mol ratio between charcol and carbon dioxide. So, the moles of carbon dioxide gas formed are equivalent to the moles of charcol. To convert the moles of carbon dioxide to grams we multiply the moles by it's molar mass.
Carbon dioxide has one carbon and two oxygen atoms so it's molar mass = 12 + 2(16) = 12 + 32 = 44
So, 44 is the molar mass of carbon dioxide and above calculations clearly shows how and where we get this.
<span>Colligative properties are dependent upon the number of molecules or ions present in solution. Therefore, 1 mole of Na2SO4 will produce 3 moles of ions and so it will have 3 times as much of an effect as 1 mole of sugar, which is not an electrolyte and can't dissociate to an appreciable extent.</span>
Well..... it would be a mechanical mixture because you use mechanical energy when you squeeze it and the mixture is the juice and the pulp.
Answer:
CH₂
Explanation:
Given parameters:
Percentage composition:
Carbon = 40.1%
Hydrogen = 6.6%
Unknown:
Empirical formula of the compound = ?
Solution:
The empirical formula of a substance is its simplest formula.
Elements Carbon Hydrogen
Percentage
Composition 40.1 6.6
Molecular mass 12 1
Number of moles 40.1/12 6.6/1
3.342 6.6
Divide through by
the smallest 3.342/3.342 6.6/3.342
1 2
So the empirical formula of the compound is CH₂