Name three places plants store energy

Water, 35 liters. Carbon, 20 kilograms. Ammonia, 4 liters. Lime, 1.5 kilograms. Phosphorous, 800 grams. Salt, 250 grams. Saltpeter, 100 grams. Sulfur, 80 grams. Fluorine, seven-point-five. Iron, five. Silicon, three grams. And trace

amounts of 15 other elements.

the ingredients of the average adult,right down to the last specks of protein in your eyelashes. And even though science has given us the entire physical breakdown, there's never been a successful attempt at bringing a human to life. There's still something missing. Something scientists haven't been able to find in centuries of research. ...and in case you're wondering, all those ingredients can be bought on a child's allowance. humans can be made rather cheap. There's no magic to it.

6 0

2 years ago

"Compounds A and B react to give a single product, C. Write the rate law for each of the following cases and determine the units

olasank [31]

Answer:

Part a: <em>Units of k is </em> $M^{-2}s^{-1}$ <em> where reaction is first order in A and second order in B</em>

Part b: <em>Units of k is </em> $M^{-1}s^{-1}$ <em> where reaction is first order in A and second order overall.</em>

Part c: <em>Units of k is </em> $M^{-1}s^{-1}$ <em> where reaction is independent of the concentration of A and second order overall.</em>

Part d: <em>Units of k is </em> $M^{-3}s^{-1}$ <em> where reaction reaction is second order in both A and B.</em>

Explanation:

As the reaction is given as

$A+B \rightarrow C$

where as the rate is given as

$r=k[A]^x[B]^y$

where x is the order wrt A and y is the order wrt B.

Part a:

x=1 and y=2 now the reaction rate equation is given as

$r=k[A]^1[B]^2$

Now the units are given as

$r=k[A]^1[B]^2\\M/s =k[M]^1[M]^2\\M/s =k[M]^{1+2}\\M/s =k[M]^{3}\\M^{1-3}/s =k\\M^{-2}s^{-1} =k$

The units of k is $M^{-2}s^{-1}$

Part b:

x=1 and o=2

x+y=o

1+y=2

y=2-1

y=1

Now the reaction rate equation is given as

$r=k[A]^1[B]^1$

Now the units are given as

$r=k[A]^1[B]^1\\M/s =k[M]^1[M]^1\\M/s =k[M]^{1+1}\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k$

The units of k is $M^{-1}s^{-1}$

Part c:

x=0 and o=2

x+y=o

0+y=2

y=2

Now the reaction rate equation is given as

$r=k[A]^0[B]^2$

Now the units are given as

$r=k[B]^2\\M/s =k[M]^2\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k$

The units of k is $M^{-1}s^{-1}$

Part d:

x=2 and y=2

Now the reaction rate equation is given as

$r=k[A]^2[B]^2$

Now the units are given as

$r=k[A]^2[B]^2\\M/s =k[M]^2[M]^2\\M/s =k[M]^{2+2}\\M/s =k[M]^{4}\\M^{1-4}/s =k\\M^{-3}s^{-1} =k$

The units of k is $M^{-3}s^{-1}$

7 0

3 years ago

22. A piece of wood board contains approximately 6.76 X 1023 molecules of wood, C2H4920, how

Licemer1 [7]

Answer:

<h2>1.23 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{6.76 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{6.76}{6.02} \\ = 1.22923...$

We have the final answer as

<h3>1.23 moles</h3>

Hope this helps you

5 0

2 years ago

Name three places plants store energy​

Name three places plants store energy