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2 years ago

15

Help me please.......... Will Give Brainlest if right

1 answer:

Zigmanuir [339]2 years ago

6 0

Answer:

The answer would be C) 64 and 112

Step-by-step explanation:

If you go through each answer and find which perimeters they would have, you would get 108 for A, 312 for B, 352 for C, and 372 for D. The question says the perimeter is equal to 352 therefore C is the answer.

You might be interested in

Help wanted and needed I’m not good at math

stealth61 [152]

Answer:

$- \frac{7}{8}$

Step-by-step explanation:

Line d slope is 8/7, therefore the perpendicular is -7/8

8 0

3 years ago

How do I solve 34-5x+2(x-2)=15

LenKa [72]

34-5x+2(x-2)=15 1st get rid of () by distributing the 2.
34-5x+2x-4=15 Now collect like terms.
30-3x=15 Get -3x by itself by subtracting 30 in both sides.
-3x=-15 You want X by itself so divide by -3 on both sides.
x=5

8 0

3 years ago

The circumference of a circle is 36pi cm what is the radius

alexdok [17]

Answer:

The radius is 18 cm

Step-by-step explanation:

The formula for circumference with radius is

C = 2*pi*r

We know the circumference is 36 pi

36 pi = 2 * pi *r

Divide by pi

36 pi/pi = 2 * pi/pi *r

36 = 2r

Divide by 2

36/2 = 2r/2

18 = r

8 0

3 years ago

In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association a

RUDIKE [14]

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

5 0

2 years ago

Find the difference between8/15 and 2/3 Show all calculations in your final answer.

kherson [118]

Answer:

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

Step-by-step explanation:

Let the value of a number 'a' be = 8/15

Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

$a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{8}{15}-\frac{-2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=\frac{8}{15}-\left(-\frac{2}{3}\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\frac{8}{15}+\frac{2}{3}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{8+10}{15}$

$=\frac{18}{15}$

$\mathrm{Cancel\:the\:common\:factor:}\:3$

$=\frac{6}{5}$

Thus,

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

3 0

3 years ago