I think I can! I recently covered algebra in 6th grade, (if that's what grade ur in) and I'm pretty good at 6th grade algebra
60*80%=
60*0.8 = 48
one of your choices should be 48 or something close to 48
<span>k+12/k=8
Multiply k to remove the k in one side
</span><span>(k+12/k=8) (k)
</span>Therefore,
k^2+12k-8k=0
Thus,
The equations he must solved now is k^2-8+12=0
Y=9(x^2+3x-x-3)
y=9(x^2+2x-3)
y=9x^2+18x-27
The correct answer is 4 and 1/8
