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3 years ago

Answer plz, i will give brainliest XD 100 points ppl, lol

Mathematics

2 answers:

castortr0y [4]3 years ago

8 0

Answer:

A) x=9, x=-2, x=2

Step-by-step explanation:

(x-9)(x+2)(x-2)=0

x-9=0

x+2=0

x-2=0

x=9, x=-2, x=2

Papessa [141]3 years ago

5 0

Answer:

im 100% sure it is Ax=9, x=-2, x=2

Step-by-step explanation:

got 100% on test please give brainliest

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In a In a school of 567 pupils 278 are boys.

DIA [1.3K]

Answer:

49% of the pupils are boys and 51% are girls.

Step-by-step explanation:

Alright, so first, you've got to find the total number of students: 567.

Now, to find the value of 1%, you divide 567 by 100, which will give you 5.67.

Next, you divide the number of male students by the value of 1%. That's 278 ÷ 5.67 = 49.0299823633157.

Subtracting that from 100% gives you 50.9700176366843 (percentage of girls)

Now, you can't write all that down, so you'll round it! 49.0299823633157 will round down, because 0 is less than 5, so it's 49%. 50.9700176366843 rounds up, because 9 is greater than 5, so that's 51%.

Therefore, 49% of the pupils are boys and 51% are girls.

I hope this helps!

4 0

3 years ago

Geometry CC 2015 Chapter 1: Perimeter and Area in the coordinate plane section Exercises 1. Exercise

gladu [14]

Answer:

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Step-by-step explanation:

3 0

4 years ago

What is the remainder when 3 is synthetically divided into the polynomial -x^2+5x-9

Maurinko [17]

-3 is the remainder when you synthetically divide

8 0

3 years ago

Read 2 more answers

X/9 = 4/15 solve the following proportions

sammy [17]

Answer:

x = 2.4

Step-by-step explanation:

x*15 = 9 * 4

15x = 9 * 4

15x = 36

x = 2.4

6 0

3 years ago

The length and width of a rectangle are measured as 30cm and 24cm, respectively, with an error in measured of

larisa [96]

Answer:

The maximum error in the calculated area of rectangle is 5.4 cm².

Step-by-step explanation:

Given : The length and width of a rectangle are measured as 30 cm and 24 cm, respectively, with an error in measured of at most 0.1 cm in each.

To find : Use differentials to estimate the maximum error in the calculated area of rectangle ?

Solution :

The area of the rectangle is $A=l\times w$

The derivative of the area is equal to the partial derivative of area w.r.t. length times the change in length plus the partial derivative of area w.r.t. width times the change in width.

i.e. $dA=\frac{\partial A}{\partial L}\Delta L+\frac{\partial A}{\partial W}\Delta W$

Here, $\frac{\partial A}{\partial L}=30,\ \frac{\partial A}{\partial W}=24 ,\ \Delta L=0.1,\ \Delta W=0.1$

Substitute the values,

$dA=(30)(0.1)+(24)(0.1)$

$dA=3+2.4$

$dA=5.4$

Therefore, the maximum error in the calculated area of rectangle is 5.4 cm².

7 0

3 years ago