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V125BC [204]
3 years ago
7

How to know if a limit exists

Mathematics
1 answer:
alekssr [168]3 years ago
7 0
THE LIMIT DOES NOT EXIST! -Mean Girls
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a line passes through the point (-9,7) and has a slope of -4/3 write an equation in point slope form for this line
DENIUS [597]
The answer would be: Y= -4/3x - 5
5 0
3 years ago
g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained
Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

                          P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of residents 65-years or older who had obtained a flu shot = \frac{28}{111} = 0.25

          n = sample of residents 65-years or older = 111

          p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } },\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

   = [ 0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } , 0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } ]

   = [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0
3 years ago
Rewrite the equation 4x + 5x2 = 8x – 7 in standard form and
Makovka662 [10]

Answer:

The correct option is a=5, b = -4, c=7 ....

Step-by-step explanation:

The standard form is ax²+bx+c=0

where a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

The given expression is:

4x + 5x2 = 8x – 7

To make it a standard equation we will move all the values to the left hand side and 0 will be left at the right hand side.

4x+5x²-8x+7=0

Now solve the like terms and arrange the equation according to the standard form:

ax²+bx+c=0

5x² - 4x +7 =0

Here a = 5

b = -4

c= 7

Thus the correct option is a=5, b = -4, c=7 ....

4 0
3 years ago
One of the local homeless shelters received a donation of 852 blankets to help support the homeless population during the harsh
Arte-miy333 [17]

Answer:

Each shelter would get 121 blankets

And there would be 5 blankets left over

Step-by-step explanation:

One of the local homeless shelters received a donation of 852 blankets to help support the homeless population during the harsh winter months. They plan on distributing them to all 7 of the local shelters. How many blankets will each shelter get? Will there be any leftover? If so, how many?

From the above question

7 local shelters = 852 blankets

1 local shelters = x blankets

Cross Multiply.

7x = 852 blankets

x = 852 blankets/7

x = 121 5/7 blankets

Therefore, Each shelter would get 121 blankets

And there would be 5 blankets left over

7 0
2 years ago
How to write five million, forty thousand
NeTakaya

That would be 5,040,000

8 0
3 years ago
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