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3 years ago

How to know if a limit exists

Mathematics

1 answer:

alekssr [168]3 years ago

7 0

THE LIMIT DOES NOT EXIST! -Mean Girls

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Otis and his 2 brother went to their favorite restaurant. Their total bill was $22.42. They used a coupon for 20% off of the tot

nevsk [136]

Answer:

$ 5.98

Step-by-step explanation:

20/100 × 22.42/1 = $ 4.48

$ 22.42 - $ 4.48 = $ 17.94

If they split that bill in two each would pay $ 5.98

I hope this helps.

4 0

3 years ago

Please solve these. Will rate you 5 star!

ziro4ka [17]

Answer: Hi!

To find the answer for question 24, we would first find the square root of 20 and 5. The square root of 20 is about 4.47 (I used a calculator for convenience) and the square root of 5 is about 2.24. Now we need to add these:

4.47 + 2.24 = 6.71

Now we divide 30 by this:

30/6.71 = 4.47

Now, we'll evaluate the answer choices.

a) is equal to 1.49

b) is equal to 13.4

c) is equal to 4.47

d) is equal to 26.88

The answer choice that is correct is c, because it is what we got for the problem that we were supposed to solve in the beginning.

Hope this helps!

7 0

3 years ago

Find the domain and range of the relation.

Kisachek [45]

the answer is in the picture above

8 0

3 years ago

Help me with this question please.

Tems11 [23]

Answer:

38.6 m

Step-by-step explanation:

cos 75° = 10/x

x= 10/cos75°= 38.637 ≈ 38.6m

8 0

3 years ago

A study of peach trees found that the average number of peaches per tree was 725. The standard deviation of the population is 70

TEA [102]

Answer:

She needs to sample 189 trees.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation of the population is 70 peaches per tree.

This means that $\sigma = 70$

How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree?

She needs to sample n trees.

n is found when M = 10. So

$M = z\frac{\sigma}{\sqrt{n}}$

$10 = 1.96\frac{70}{\sqrt{n}}$

$10\sqrt{n} = 1.96*70$

Dividing both sides by 10:

$\sqrt{n} = 1.96*7$

$(\sqrt{n})^2 = (1.96*7)^2$

$n = 188.2$

Rounding up:

She needs to sample 189 trees.

3 0

3 years ago