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3 years ago

It took Jamal 18 minutes to jog 4 laps. How many minutes did it take to jog each lap?

Mathematics

1 answer:

MAXImum [283]3 years ago

7 0

Answer:

4.5 minutes per 1 lap.

Step-by-step explanation:

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Through:(2,-5),slope=3/2

Rainbow [258]

Are you trying write it into slope intercept form ?

8 0

2 years ago

Is a number of television in a household a discrete quantitative or continuous quantitative

mezya [45]

discrete, you cannot have 1.5 televisions

generally the number of X is a discrete variable.

continous = can contain decimal value (float values)

discrete = no decimal (integers)

7 0

3 years ago

Calculating area of rectangle

PSYCHO15rus [73]

Answer:

$Area = 216.108cm^2$ --- You

$Area = 216.940cm^2$ --- Another student

Reason: Because there is a variation in the given dimensions

Step-by-step explanation:

Given

Your measurement

$Length = 20.70cm; Width =10.44cm$

Another students'

$Length = 20.74cm; Width =10.46cm$

Solving (a): The area

Area is calculated as:

$Area = Length * Width$

For you

$Area = 20.70cm * 10.44cm$

$Area = 216.108cm^2$

For the other student

$Area = 20.74cm * 10.46cm$

$Area = 216.940cm^2$

Solving (b): Reason for the variation in the areas

The given measurements are estimates of the dimensions of the rectangle.

Since there is a variation in the estimates, there will be some level of variation in the calculated area.

4 0

3 years ago

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

6 0

3 years ago

Help!!!!!!!<br> I need to find the surface area of this image.

Kaylis [27]

Answer:

length;12cm

Step-by-step explanation:

3 0

3 years ago

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