Answer:
A. No solutions
Step-by-step explanation:
2x-2x=-9
0= -9
Since 0 does not equal -9, there are no solutions.
Answer:
option f is right
Step-by-step explanation:
Given that data is collected to perform the following hypothesis test.

(right tailed test)
Sample mean = 5.4
p value = 0.1034
when p value = 0.1034 we normally accept null hypothesis. i.e chances of null hypothesis true is the probability of obtaining test results at least as extreme as the results actually observed during the test, assuming that the null hypothesis is correct
f) If the mean µ does not differ significantly from 5.5 (that is, if the null hypothesis is true), then the probability of obtaining a sample mean y as far or farther from 5.5 than 5.4 is .1034.
.
Answer:
a right angle
Step-by-step explanation:
The best and most correct answer among the choices provided by the question is the second choice "a right angle"The formula for finding the slope of a line on a coordinate plane is (y2 - y1) / (x2 - x1), where (x2, y2) and (x1, y1) represent two distinct points on the line. This is also known as "change in y over change in x" or "rise over run."I hope my answer has come to your help. God bless and have a nice day ahead!
Correct answer is: distance from D to AB is 6cm
Solution:-
Let us assume E is the altitude drawn from D to AB.
Given that m∠ACB=120° and ABC is isosceles which means
m∠ABC=m∠BAC = 
And AC= BC
Let AC=BC=x
Then from ΔACD , cos(∠ACD) = 
Since DCB is a straight line m∠ACD+m∠ACB =180
m∠ACD = 180-m∠ACB = 60
Hence 

Now let us consider ΔBDE, sin(∠DBE) = 

If 12 types only last 4 days, and the rest last an average of 6, then the average amount of days that ALL the flowers wilt would be 5. To find the average, you add 6 and 4 to get 10, and since there is only 2 number we added togehter to get 10, you would divide 10 by 2 to get 5!