Let x = length of side of the square. Then area of the square is
A(x) = x^2
You are also told that dx/dt = 6 cm/s
Now, you want to find dA/dt when A = 16, i.e., when x = 4.
Since
dx/dt = 6cm/s
and
dA/dx = 16cm/s
dA/dx dx/dt
= dA/dt
dA/dt A' = 2xx'
A' = 2x6cm/s
So we need to solve for x because we are trying to find dA
<span>so
</span>16 = x^(2)
(16)^(1/2) = 4
<span>thus
</span>
A' = 2(4)(6)
A' = 48
Answer:
Step-by-step explanation:
Integer roots:
a = 6 n + 1, b = 7, c = -3 n^2 - n, n element Z
a = 6 n + 5, b = 7, c = -3 n^2 - 5 n - 2, n element Z
Derivative:
d/da(1/7 (a^2 + 12 c) b - 1) = (2 a b)/7
Indefinite integral:
integral(-1 + 1/7 b (a^2 + 12 c)) da = (a^3 b)/21 + (12 a b c)/7 - a + constant
Related Queries:
You need to find x for both equations first
3x - 11 < 4 4x + 9 ≥ 1
+ 11. +11. -9. -9
3x < 15 4x ≥ -8
/3. /3 /4. /4
X < 5 X ≥ -2
Then you plug in x in the equations
3(5) - 11 < 4. 4(-2) + 9 ≥ 1
15 - 11 < 4 -8 + 9 ≥ 1
4 < 4 1. ≥ 1
False True
Answer:
Where is the question?
Step-by-step explanation:
Answer:
none
Step-by-step explanation:
The given information is not enough to prove the triangles are congruent.