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Flura [38]
2 years ago
6

Are these the correct answers?

Mathematics
1 answer:
Ronch [10]2 years ago
7 0

Answer:

b is incorrect

Step-by-step explanation:

you should write out 0 10 times, 1 5 times, 2 5 times, 3 4 times and 4 1 time. then see what's in the middle of that.

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Imeldas jigsaw puzzle has 500 pieces. She estimates that she put togethe approximately 95 of the pieces.
tekilochka [14]

Answer:

19% done

81% left

Step-by-step explanation:

95/500=19

100-19=81

7 0
3 years ago
Which method can be used to find the interquartile range for a set of data ?
nignag [31]
The interquartile range (IQR) can be found by finding the difference of the upper and lower quartiles
6 0
3 years ago
Read 2 more answers
What’s 22,000 - 407% of 60?
DENIUS [597]

Answer:

21,755.8

Step-by-step explanation:

To solve this equation, we must first find 407% of 60.

To do this, place the percent over 100 (fraction form), then, multiply it by the number you're finding the percentage of.

407/100 x 60/1 = 24,420/100

24420 / 100 = 244.2

244.2 is 407% of 60.

Lastly, you subtract 244.2 from 22,000.

22,000 - 244.2 = 21,755.8

4 0
2 years ago
Let f(x)=−1/4(x+4)^2−8 . What is the average rate of change for the quadratic function from x=−2 to x = 2? Enter your answer in
kiruha [24]

Answer:

Average rate of change of function is -2.

Step-by-step explanation:

Given f(x)=\frac{-1}{4}(x+4)^2-8.

we have to find the average rate of change for the quadratic function from x=−2 to x = 2.

f(-2)=\frac{-1}{4}(-2+4)^2-8=\frac{-1}{4}(4)-8=-9

f(2)=\frac{-1}{4}(2+4)^2-8=\frac{-1}{4}(36)-8=-17

The average rate of change of the function  f(x) on interval [-2,2] is

\frac{f(b)-f(a)}{b-a}=\frac{f(2)-f(-2)}{2-(-2)}=\frac{-17-(-9)}{4}=\frac{-8}{4}=-2

3 0
3 years ago
What is the interquartile range (IQR) of this data set?
Andreas93 [3]

Answer:

11 is the median of the entire data set

6 is the median of the lower half and 16 is the median of the upper half data scores...

Subtract 16 from 6 gives 10 so the answer is C) 10

7 0
2 years ago
Read 2 more answers
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