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Rudik [331]
2 years ago
8

This is due today pls help

Mathematics
1 answer:
umka2103 [35]2 years ago
6 0

Answer: the answer is linear

Step-by-step explanation: (not sure what functions it’s talkin about but it is linear)

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1/(x-2)+1/(x+3)=1/5 solve the problem for me​
Gennadij [26K]

════════ ∘◦❁◦∘ ════════

<h3>Final value : x² -9x - 11</h3>

════════════════════

<h3>Step by step </h3>

\frac{1}{(x - 2)}  +  \frac{1}{(x + 3)}  =   \frac{1}{5}

\frac{(x + 3) + (x - 2)}{(x - 2)(x + 3)}  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2} + 3x - 2x - 6 }  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2}  + x - 6}  =  \frac{1}{5}

2x + 1 = ⅕ × (x² + x - 6)

2x + 1 = ⅕x² + ⅕x - 6/5

1/5x² +1/5x - 2x - 6/5 - 1 = 0

1/5x² -9/5x - 11/5 = 0

x² - 9x - 11 = 0. #times by 5

════════════════════

#Give me brainliest pls im tired typing all of this

8 0
3 years ago
F(x)=x 2 +10f, left parenthesis, x, right parenthesis, equals, x, squared, plus, 10 What is the average rate of change of fff ov
pav-90 [236]

Answer:

Average rate of change=-3

Step-by-step explanation:

The average rate of change is given by the relation between the values of f(x) and x, in two different points as follows:

Change=\frac{f(x_{2})- f(x_{1})}{x_2-x_1}

In this case, x_{1}=-2; x_{2}=-1

Therefore,

Change=\frac{((-1)^{2}+10) -((-2)^{2}+10)}{-1-(-2)}=\frac{11-14}{1}=-3

3 0
3 years ago
Read 2 more answers
Older people often have a hard time finding work. AARP reported on the number of weeks it takes a worker aged 55 plus to find a
mote1985 [20]

Answer:

34

Step-by-step explanation:

?

3 0
2 years ago
Read 2 more answers
Can someone help me with this?
abruzzese [7]
A) vertical angles
B) same side interior angles
C) alternate interior angles
D) corresponding angles
3 0
3 years ago
Evaluate the following integral using trigonometric substitution.
wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function \int\limits {\sqrt{a^{2} -x^{2} } } \, dx, using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as asin \theta i.e x = a sin\theta.

All integrals in the form \int\limits {\sqrt{a^{2} -x^{2} } } \, dx are always evaluated using the substitute given where 'a' is any constant.

From the given integral, \int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx where a = 7 in this case.

The substitute will therefore be   x = 7 sin\theta

2.) Given x = 7 sin\theta

\frac{dx}{d \theta} = 7cos \theta

cross multiplying

dx = 7cos\theta d\theta

3.) Rewriting the given integral using the substiution will result into;

\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta  } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)}   } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)}   }}} \, 7cos\theta d\theta\\

= \int\limits343 cos^{2}  \theta \, d\theta

8 0
3 years ago
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