3 years ago

Please help me, yall :))))

1 answer:

4 0

Choose A or C that’s all on u

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Rudiy27

Answer: $\bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}$

<u>Step-by-step explanation:</u>

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x

$\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}$

Restriction on x: the denominator cannot be equal to zero. So,

x(3x - 2) ≠ 0

→ x ≠ 0 and 3x - 2 ≠ 0

3x ≠ 2

x $\neq \dfrac{2}{3}$

8 0

3 years ago

Basile [38]

We can say that the other number is even or it is 0.

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3 years ago

Korvikt [17]

Answer:

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Step-by-step explanation:

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vivado [14]

Step-by-step explanation:

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Len [333]

Answer:

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Step-by-step explanation:

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