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tia_tia [17]
3 years ago
12

Help me please!!!!!!!

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

The correct answer is 2860

Step-by-step explanation:

Kim multiplied 14.3 by 2, not 200

insens350 [35]3 years ago
6 0

Answer:

19.508

Step-by-step explanation:

maaf kalo salah ya vangkee makasih

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A bookstore wants to determine how many books the people in the surrounding neighborhood read per month on average. they survey
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Answer:

Step-by-step explanation:

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3 years ago
The formula to convert degrees Celsius to degrees Fahrenheit is 9/5 C + 32 equals F use this equation to find the Celsius equiva
ehidna [41]

Answer:

  86 °F = 30 °C

Step-by-step explanation:

Put the given number in the equation and solve for C.

  86 = 9/5C +32

  54 = 9/5C

  (5/9)54 = C = 30

The equivalent is 30 degrees Celsius.

8 0
3 years ago
Solve the system of linear equations by multiplying. Check the answer by graphing the system of equations. –2x + 2y = 10 -4x + 5
kari74 [83]

Answer:

x=2, y=7 (2,7)

Explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

8 0
3 years ago
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
Use the Distributive Property to simplify this expression.<br> 15. (7 + 6w)6
antiseptic1488 [7]

(7+6w)6

 7 x 6 = 42

 6 x 6 = 36

so it becomes:

42 +36w

7 0
4 years ago
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