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3 years ago

The two polygons below are similar.

Mathematics

2 answers:

IrinaK [193]3 years ago

8 0

Answer:

Similarity statement is a little mixed up.

Step-by-step explanation:

Your similarity statement is a little off. The order in the statement DOES MATTER. For example angle E corresponds with angle V or T (∠V≅∠T). These would be correct...

CDEF similar TUVS
CDEF similar TSVU
CDEF similar VSTU
CDEF similar VUTS

...**

FEDC similar UTSV
FEDC similar STUV**

**There are a lot but the first letter of the first polygon corresponds with the first letter of the second polygon and so on. That is the only way this statement is true. There are about a 96 different combinations for this so any one would work.

The similarity ratio is the same thing as asking "what value would make the first polygon congruent to the second"? In this case 1(x) = 4, x = 4. Therefore the ratio is 4, or 4/1 (if asked can also be written as 4:1. THE ORDER IS ALSO VERY IMPORTANT.

ddd [48]3 years ago

3 0

Answer:

The similarity ratio is 4 4/1 or 4

Step-by-step explanation:

You find that one of them has side lengths of 1 and the other has side lengths of 4

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fredd [130]

Answer:

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Step-by-step explanation:

Note that the radii of all the structures are the same.

Let the height of the cone be H and the height of the cylinder be h

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To obtain this, we equate the volume of those two structures

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πr² cancels out on both sides and we're left with

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2) The ratio of the height of the cone to radius of the sphere

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(1/3)πr²H = (4/3)πr³

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Step-by-step explanation:

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