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Gemiola [76]
2 years ago
6

Find the product of theL.C.M and H.C.F of 8 and 12.​

Mathematics
2 answers:
NikAS [45]2 years ago
6 0

Answer:

24*4=96

Step-by-step explanation:

lcm of 8 and 12 is 24

hcf of 8 and 12 is 4

24 times 4 = 96

V125BC [204]2 years ago
3 0

Answer:

<h3>96 is the answer. </h3>

Step-by-step explanation:

<h3>The L.C.M of 8 and 12 is 24</h3><h3>The H.C.F of 8 and 12 is 4</h3>

<h3>We multiply </h3><h3>24 *4 we shall get 96 as the answer. </h3><h3 />
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Solve the following, round to 2 decimal places. <br>36.67 ÷ 12​
Lubov Fominskaja [6]
So 36.67\12= 3.055833 and the 3 repeats so round up the 5 to get 3.06
Hope I’m correct!
5 0
3 years ago
Read 2 more answers
What are the square roots of 144 over 256
stepladder [879]
Minus 12 over 16 and 12 over 16 

There you go!
8 0
3 years ago
Read 2 more answers
The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds. A sampl
Westkost [7]

Answer:

1963.2 pounds (lbs.)

Step-by-step explanation:

Things to understand before solving:

  • - <u>Normal Probability Distribution</u>
  1. The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by: Z=\frac{X-u}{a}

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.

  • - <u>Central Limit Theorem</u>
  1. The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц  and standard deviation s=\frac{a}{\sqrt{n} }

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.

This means, ц  = 2000 and б = 100.

A random sample of 20 cables is chosen and tested.

This means that n = 20, s=\frac{100}{\sqrt{120} } =22.361

Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.

This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So Z=\frac{X-u}{a}

  • By the Central Limit Theorem

Z=\frac{X-u}{a} \\-1.645=\frac{X-2000}{22.361} \\X-2000=-1.645*22.361

X =1963.2

<h3>Answer:</h3>

The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.

3 0
3 years ago
What do the following two equations represent?<br> -4x-4y = -5 <br> 12x+12y = 112x
7nadin3 [17]

Answer:

These two lines are parallel and system of these equations have no solution

Step-by-step explanation:

Parallel Lines: Lines having same slope and different x and y intercept are parallel lines. System of such equations does not have any solution as these lines does not intersect at any finite points.

Standard form of line is y=mx+c where m is slope and c is y-intercept.

First Line:

-4x-4y=-5\\\\-4y=-5+4x\\\\Divide\ both\ sides\ by\ -4\\\\y=-x+\frac{5}{4}\\\\compare\ with\ y=mx+c\\\\slope=-1,\ c=\frac{5}{4}

Second Line:

12x+12y=112\\\\12y=112+-12x\\\\Divide\ both\ sides\ by\ 12\\\\y=-x+\frac{12}{112}\\\\compare\ with\ y=mx+c\\\\slope=-1,\ c=\frac{12}{112}

Hence these two lines are parallel and system of these equations have no solution

4 0
3 years ago
Quick need help for this question
Tasya [4]
It’s c I did this in my class
6 0
3 years ago
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