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3 years ago

Write an explicit formula for an, the nth term of the sequence 6,18,54,... Pls help

Mathematics

1 answer:

frez [133]3 years ago

5 0

Step-by-step explanation:

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Hurry please!!! Fast response

AlladinOne [14]

Answer:

$SA= \frac{2}{3} \pi rl+16 \pi r^2$

Step-by-step explanation:

Surface area of the original cone

$SA= \pi r l + \pi r^2... (1)$

When, radius is quadrupled and slant height is reduced to one sixth

$i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l$

Plug the above values of r and $l$ in equation (1), new surface area becomes:

$SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2$

$SA= \frac{4}{6} \pi rl+16 \pi r^2$

$\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}$

8 0

3 years ago

The average discharge at the mouth of the Amazon River is 4,900,000 cubic feet per second. How much water is discharged from the

Misha Larkins [42]

Answer: Average discharge at the mouth of the Amazon River in 1 hour = $1.764\times 10^{10}$ cubic feet

Average discharge at the mouth of the Amazon River in 1 year= $3.66912\times10^{13}$ cubic feet[/tex]

Step-by-step explanation:

Given : The average discharge at the mouth of the Amazon River =4,900,000 cubic feet per second.

i.e. The average discharge at the mouth of the Amazon River in 1 second= 4,900,000 cubic feet

Since 1 hour = 3600 seconds

Then , the average discharge at the mouth of the Amazon River in 1 hour =

$4900000\times3600=17640000000$ cubic feet

Since , there are 2080 hours in a typical year.

Then, the average discharge at the mouth of the Amazon River in 1 year=

$2080\times17640000000\\\\=36,691,200,000,000=3.66912\times10^{13}$ cubic feet

6 0

3 years ago

The length of a rectangle is five times its width.

grandymaker [24]

Answer:

length =30m width=6m

hope it helps

3 0

3 years ago

How to solve this math equation -9x ≥-90

olga2289 [7]

X<_10. ..............
...

3 0

3 years ago

Read 2 more answers

10. What is the value of x in the solution to the system of equations?

RUDIKE [14]

Solve for x in first equation:

x-2y=7

Add “2y” to both sides

x=2y+7

Put this in to second equation:

3(2y+7)+2y=21

Solve for y:

Distribute the 3 into the ()

6y+21+2y=21

Combine the like y terms

8y+21=21

Subtract 21 from both sides

8y=0

Divide by 8 on both sides

y=0

Put this into the first solved equation:

x=2(0)+7

Solve for x:

Multiple 2(0)

x=0+7

Add 0 and 7

x=7

So the value of x is positive 7.

3 0

3 years ago