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Katen [24]
3 years ago
5

On a certain day the temperature in Austin was 10.2°C and the temperature in New York City was -4.8°C. ​What is the difference i

n temperature between the two cities​?
Show your work please and if you do you get 60 points!!!!
good luck and please don't get the wrong answer. it took me a long time to get the points so please and good luck!
Mathematics
1 answer:
Flura [38]3 years ago
8 0

Answer:

15°C

Step-by-step explanation:

Find the difference by subtracting -4.8 from 10.2

10.2 - (-4.8)

Subtracting a negative number changes to adding a positive number:

10.2 + 4.8

= 15

So, the difference in temperature between the two cities is 15°C

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Y is directly proportional to x2.<br> If y = 112 when x = 4 find<br> y when x = 9<br> y=
elena-s [515]

Answer:

112-4

y-9

4y=112*9

4y=1008

y=1008/4

y=252

have a nice day .

hope this helps

7 0
3 years ago
Steve earns $8 per hour. His older brother earns $2 more per hour than Steve. What is the ratio of the money Steve earns in an h
Licemer1 [7]
Answer: 4:5

Explanation:

Steve earns 8 dollars an hour. His brother earns 10 dollars an hour.

The ratio is Steve:Brother, which is 8:10.

This can be treated the same was as a fraction and simplified, dividing both sides by 2, which becomes 4:5
5 0
3 years ago
1433.4 to the nearest 10
frozen [14]

Answer:

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4 0
3 years ago
Which table shows a no change linear relationship?
Phantasy [73]

Answer:

C

Step-by-step explanation:

Each of the tables is a linear relationship. Linear relationships increase or decrease steadily by adding or subtracting a constant. Table A increases by 5. Table B decreases by 2. Table C doesn't change. Table D increase by 4.

A "no change" means the y values never change. The constant is 0 and is a horizontal line. Table C is the solution.

8 0
3 years ago
Read 2 more answers
The U.S. government has devoted considerable funding to missile defense research over the past 20 years. The latest development
Bad White [126]

Answer:

a) Let the random variable X= "number of these tracks where SBIRS detects the object." in order to use the binomial probability distribution we need to satisfy some conditions:

1) Independence between the trials (satisfied)

2) A value of n fixed , for this case is 20 (satisfied)

3) Probability of success p =0.2 fixed (Satisfied)

So then we have all the conditions and we can assume that:

X \sim Bin(n =20, p=0.8)

b) X \sim Bin(n =20, p=0.8)

c) P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

d) P(X \geq 15) = P(X=15)+ .....+P(X=20)

P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

P(X=16)=(20C16)(0.8)^{16} (1-0.8)^{20-16}=0.218

P(X=17)=(20C17)(0.8)^{17} (1-0.8)^{20-17}=0.205

P(X=18)=(20C18)(0.8)^{18} (1-0.8)^{20-18}=0.137

P(X=19)=(20C19)(0.8)^{19} (1-0.8)^{20-19}=0.058

P(X=20)=(20C20)(0.8)^{20} (1-0.8)^{20-20}=0.012

P(X\geq 15)=0.804208

e) E(X) = np = 20*0.8 = 16

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

Let the random variable X= "number of these tracks where SBIRS detects the object." in order to use the binomial probability distribution we need to satisfy some conditions:

1) Independence between the trials (satisfied)

2) A value of n fixed , for this case is 20 (satisfied)

3) Probability of success p =0.2 fixed (Satisfied)

So then we have all the conditions and we can assume that:

X \sim Bin(n =20, p=0.8)

Part b

X \sim Bin(n =20, p=0.8)

Part c

For this case we just need to replace into the mass function and we got:

P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

Part d

For this case we want this probability: P(X\geq 15)

And we can solve this using the complement rule:

P(X \geq 15) = P(X=15)+ .....+P(X=20)

P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

P(X=16)=(20C16)(0.8)^{16} (1-0.8)^{20-16}=0.218

P(X=17)=(20C17)(0.8)^{17} (1-0.8)^{20-17}=0.205

P(X=18)=(20C18)(0.8)^{18} (1-0.8)^{20-18}=0.137

P(X=19)=(20C19)(0.8)^{19} (1-0.8)^{20-19}=0.058

P(X=20)=(20C20)(0.8)^{20} (1-0.8)^{20-20}=0.012

P(X\geq 15)=0.804208

Part e

The expected value is given by:

E(X) = np = 20*0.8 = 16

5 0
3 years ago
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