Answer:
the choice of a glider to hanging mass is a ratio of 20.2
Explanation:
The Newton´s second law for glider is:
Fnet=Ma
T=Ma
The Newton´s second law for hanging mass is:
Fnet=ma
mag-T=ma
Replacing:
mag-Ma=ma (eq. 1)
Clearing a:
a=(mg)/(m+M)
The expression for motion is:


Clearing a:

Replacing values:

From eq. 1:
M/m=20.2
Consider horizontal component:
Using the formula:v2=u2+2a<span>s</span>
<span>0=(16sin<span>470</span><span>)2</span>+2(−9.81)s</span><span>s=6.98m</span><span>=7.0m(2s.f.)</span>The maximu height from the ground is 8.5m
I would say vibrations, but is there choices?
X=.5a(t^2), x=70m, t=3.6s, a=?. a=140/(3.6^2)=10.8m/s^2.