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3 years ago

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Why do fields store potential energy? an object in the field has charge, fields don’t store potential energy, stationary objects

within the field will move when released, or an object in the field has mass. Please help me,which one?

1 answer:

SpyIntel [72]3 years ago

6 0

Answer:

Hey

Your answer would be:

stationary objects within the field will move when realesed.

The reason why is because fields store potential energy as you know. when something is stationary it has potential, but when it is released that potential energy turns into kinetic energy.

this made me think of a funny joke:

A man was about to jump off of the Empire State Building when a physicist from below yield, Wait don't! you have so much potential!

lol always cracks me up.

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A 75 kg baseball player runs at a velocity of 6 m/s before sliding to a stop at second base. a. What is the kinetic energy of th

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Answer:

a. $\displaystyle k_o=1350\ J$

b. $\displaystyle k_1=0\ J$

c. $\Delta k=-1350\ J$

d. $W=-1350\ J$

e. $F=-675\ N$

Explanation:

<u>Work and Kinetic Energy </u>

When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:

$\Delta k=k_1-k_0$

Knowing that

$\displaystyle k=\frac{mv^2}{2}$

We have

$\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

The work done by the force who caused the change of velocity (acceleration) is

$\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

If we know the distance x traveled by the object, the work can also be calculated by

$W=F.x$

Being F the force responsible for the change of velocity

The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops

a. Before the slide, his initial kinetic energy is

$\displaystyle k_o=\frac{mv_0^2}{2}$

$\displaystyle k_o=\frac{(75)6^2}{2}$

$\boxed{\displaystyle k_o=1350\ J}$

b. Once he reaches the base, the player is at rest, thus his final kinetic energy is

$\displaystyle k_1=\frac{(75)0^2}{2}$

$\boxed{\displaystyle k_1=0\ J}$

c. The change of kinetic energy is

$\Delta k=k_1-k_0=0\ J-1350\ J$

$\boxed{\Delta k=-1350\ J}$

d. The work done by friction to stop the player is

$W=\Delta k=k_1-k_0$

$\boxed{W=-1350\ J}$

e. We compute the force of friction by using

$W=F.x$

and solving for x

$\displaystyle F=\frac{W}{x}$

$\displaystyle F=\frac{-1350\ J}{2\ m}$

$\boxed{F=-675\ N}$

The negative sign indicates the force is against movement

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A hard rubber ball on a string is being used as a pendulum. When you first look at the pendulum, the ball is being held to one s

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Answer:

<h2>Total thermal energy for all air molecules is 59.54 J</h2>

Explanation:

As we know that the ball comes to rest finally so here we can say that

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So here we have

$E_{th} = mgh$

$E_{th} = (6.2 kg)(9.8 m/s^2)(0.98 m)$

So here we have

$E_{th} = 59.54 J$

So all the gravitational potential energy of the ball will convert into thermal energy of air molecules which is equal to 59.54 J

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Answer:

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Answer:

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