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Arada [10]
3 years ago
10

a hockey player exerts a force of 5 N over a distance of 0.3 m on a hockey puck. How much work is done on the hockey puck

Physics
1 answer:
Katen [24]3 years ago
7 0

Answer: W = 1.5 J

Explanation: Work is the product of force and distance. It can be expressed in the following formula W = Fd.

W = Fd

    = 5 N ( 0.3 M )

    = 1.5 J

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We could determine the acceleration using this formula
\boxed{a= \dfrac{v_{1}-v_{0}}{t} }

Given from the question v₀ = 23 m/s, v₁ = 0 (the car stops), t = 5 s
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a= \dfrac{v_{1}-v_{0}}{t}
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After a wave passes through a medium, particles in the medium
sertanlavr [38]

Answer:

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3 0
3 years ago
If an object is thrown upward with an initial velocity of 128 ​ft/second, then its height after t seconds is given by the follow
IrinaK [193]

Answer:

The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

Explanation:

Given that,

Initial velocity u= 128 ft/sec

Equation of height

h = 128t-32t^2....(I)

(a). We need to calculate the maximum height

Firstly we need to calculate the time

\dfrac{dh}{dt}=0

From equation (I)

\dfrac{dh}{dt}=128-64t

128-64t=0

t=\dfrac{128}{64}

t=2\ sec

Now, for maximum height

Put the value of t in equation (I)

h =128\times2-32\times4

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(b). The number of seconds it takes the object to hit the ground.

We know that, when the object reaches ground the height becomes zero

128t-32t^2=0

t(128-32t)=0

128=32t

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3 0
3 years ago
Fill out the blanks, this is for science!
dusya [7]
Faster and higher I believe.
8 0
3 years ago
Read 2 more answers
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