Answer:
The answer for this problem is at the bottom of picture.
Answer:the balance after 7 years is $3216
Step-by-step explanation:
A) Initial amount deposited into the account is $2800 This means that the principal,
P = 2800
It was compounded yearly. This means that it was compounded once in a year. So
n = 1
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for 7 years. So
t = 7
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. Therefore
A = 2800(1 + 0.04/2)^ 1× 7
A = 2800(1 + 0.02)^7
A = 2800(1.02)^7
A = $3216
A. Factor the numerator as a difference of squares:

c. As

, the contribution of the terms of degree less than 2 becomes negligible, which means we can write

e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling


In particular,


so we have

For

and

, we can simplify the first term:

So our limit becomes
Answer:
5.403×10⁶
Step-by-step explanation:
5.403×10⁶= 5004300
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