Let
a1=1/40
a2=4/40
a3=9/40
a4=16/40
a5=25/40
a6=?
we know that
a2-a1=4/40-1/40----> 3/40
a3-a2=9/40-4/40-----> 5/40
a4-a3=16/40-9/40----> 7/40
a5-a4=25/40-16/40---> 9/40
the difference is
3/40,5/40,7/40.9/40,....
3/40+[2/40]---> 5/40
5/40+[2/40]---> 7/40
7/40+[2/40]---> 9/40
the next will be
9/40+[2/40]-----> 11/40
so
the next term is 25/40+[11/40]------> 36/40
the answer is
36/40
Answer:
Is not correct
Step-by-step explanation:
Step 1
Find 
divided by 
Step 2
Find 
times 
Compare
This gives us
We can take 4x from each term to get
as your answer
Solve for x. so first u would subtract 25 from 25 and 298. 25 will be crossed out so now u are left with 13x<273. to solve that, divide 13 on both sides. 13 would be crossed or so now u are left with x<13. that means x can equal anything less than 13. idk about the rest, i think u can do it. :)
