I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.
2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)
Next, I add 20 on both sides.
2x + 90 + 3x = 200º
I combine like terms (2x and 3x)
5x + 90 = 200º
I subtract 90 from both sides.
5x = 110º
Divide 110 by 5 to get x.
x = 22
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For problem two, I label all the angles I know.
49º + 80º + r = 180º
I add 80 and 49.
129º + r = 180º
I subtract 180 and 129 and get 51º, which is your angle for R.
For angle X, you know that angle R plus angle X equals half of a circle, which is 180º
We know from before that 129º is 180º without R, so X is 129º
I hope this helps! Let me know if I'm wrong!
Answer:
11
Step-by-step explanation:
If two chords intersect in a circle, the product of the lengths of the segments of one chord equal the product of the segments of the other.
AC *CB = CD CE
4 * (10-4) = CD * 8
4 * 6 = 8 *CD
24 = 8 CD
Divide each side by 8
24/8 = CD
3 = CD
We want the length DE
DE = CD + CE
= 3 + 8
DE = 11
Answer:
21
Step-by-step explanation:
0 + 1 = 1
1 + 2 = 3
3 + 3 = 6
6 + 4 = 10
10 + 5 = 15
15 + 6 = 21
Each number is added to an increase of 1 - first add 1, then add 2, then add 3,etc
Not listed but next would be 21 + 7 = 28
so it would be 0, 1, 3, 6, 10, 15, 21, 28
M = -2 and b = 3
so equation
y = -2x + 3
hope it helps
Answer:
11 students
Step-by-step explanation:
We can see that there are 6 students with 3 siblings, 4 students with 4 siblings, and 1 student with 6 siblings.
Adding all of these together will tell us how many students have 3 or more siblings.
6 + 4 + 1 = 11
So, there are 11 students with 3 or more siblings.
