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Contact [7]
3 years ago
9

How do you solve this equation: 1988 = 28(p + 15)

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

see Below

Step-by-step explanation:

Let's solve your equation step-by-step.

1988=28(p+15)

Step 1: Simplify both sides of the equation.

1988=28(p+15)

1988=(28)(p)+(28)(15)(Distribute)

1988=28p+420

Step 2: Flip the equation.

28p+420=1988

Step 3: Subtract 420 from both sides.

28p+420−420=1988−420

28p=1568

Step 4: Divide both sides by 28.

28p

28

=

1568

28

p=56

Answer:

p=56

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frutty [35]

Answer:

  • h = (S- 2πr²)/(2πr)

Step-by-step explanation:

<u>Given</u>

  • Formula S = 2πr² + 2πrh

<u>Solve for h</u>

  • S = 2πr² + 2πrh
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4 0
3 years ago
(−5)3x7(yz)4 / (3)2x2y8z2
g100num [7]

Answer:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

Step-by-step explanation:

Given:

The expression to simplify is given as:

\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}

In order to simplify this, we have to use the law of indices.

1. (ab)^m=a^mb^m

So, (yz)^4=y^4z^4

Substitute this value in the above expression. This gives,

=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)

Now, we use another law of indices.

2. \frac{a^m}{a^n}=a^{m-n}

So,  \frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2

Substitute these values in the above expression. This gives,

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Finally, we further simplify it using the law a^{-m}=\frac{1}{a^m}

So, y^{-4}=\frac{1}{y^4}

Therefore, the given expression is simplified as:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

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Step-by-step explanation:

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