Answer:
option 1) 50
Step-by-step explanation:
Let m and w denote the men and women respectively.
From the question, if the groom invited w number of women, then bride invited 2w number of women.
Also, if the bride invited m number of men,then the groom invited 2m.
Hence we can write the following maths equation:
w+2m=105.........1
2w+m=135.........2
We multiply eqn(1) by 2 to get eqn(3)
This implies that,
2w+4m=210.......3
We then subtract eqn (2) from eqn(3) to obtain;
3m=75
we divide through by 3


Substituting the value of m into eqn (1)
to find the value for w

subtracting 50 from both sides.



So we can say the :
bride invited 25 men and 110 women,
groom invited 50 men and 55 women.
Answer:
X=-4, y=-7
Step-by-step explanation:
6x-5y=11. 1st equation
y=7x+21 2nd equation
6x-5(7x+21)=11. Sub value of y in 2nd equation (7x+22) into 1st equation
6x-35x-105=11. Solve by distributative property
-29x-105=11. Add x values
-29x=116. add 105 to both sides
x=-4. Solve for x
solve for y:
y=7x+21
y=7(-4)+21
y=-28+21
y=-7
check answer by substituting x and y into either equation
6x-5y=11
6(-4)-5(-7)=11
-24+35=11
11=11
Add 6 to both sides
Solution: k = -30
Answer: 20/3
Step-by-step explanation: 3*6=18+2=20