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V125BC [204]
3 years ago
8

A textbook search committee is considering 13 books for possible adoption. The committee has decided to select 3 of the 13 for f

urther consideration. In how many ways can it do​ so?
11.8 #8
Mathematics
1 answer:
laiz [17]3 years ago
8 0

Number of ways in which the 3 can be selected from 13  = 286

Step-by-step explanation:

Step 1:

Number of books considered by the textbook search committee = 13

Number of books selected from this 13 = 3

We need to determine number of ways in which the 3 can be selected from the 13

Step 2 :

The order of the 3 books selected does not matter. So,

Number of ways in which the 3 books can be selected from 13 books =  C(13,3) = \frac{13!}{10! . 3!}

                                                                                             =\frac{ 13 . 12 .11  . 10!}{10! . 3! }

                                                                                             =\frac{1716}{6} = 286

Step 3 :

Answer :

Number of ways in which the 3 can be selected from 13  = 286

                                                                 

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Step-by-step explanation:

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8 0
3 years ago
-3 + x = 7.2; x =<br> -4w=-10;w=
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Answer:

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Step-by-step explanation:

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On a town map, each unit of the coordinate plane represents 1 mile. Three branches of a bank are located at A(−3, 1), B(3, 3), a
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Answer:

The minimum total distance the employee may have driven before getting stuck in traffic is 8.3 miles

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of the distance between to points (x_{1},y_{1})

  and (x_{2},y_{2}) i s d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

- So at first we will find the distance between the three points

∵ A = (-3 , 1) , B = (3 , 3) , C = (3 , -1)

- By using the rule of distance

∴ AB=\sqrt{(3--3)^{2}+(3-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325

∴ BC=\sqrt{(3-3)^{2}+(-1-3)^{2}}=\sqrt{0+16}=4

∴ AC=\sqrt{(3--3)^{2}+(-1-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325

∵ Each unit coordinate plane represents 1 mile

∵ AB = 6.3 units

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∵ BC = 4 units

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∴ The distance between branches A and C = 6.325 miles

- A bank employee drives from Branch A to Branch B and then

 drives halfway to Branch C before getting stuck in traffic

∵ The distance from branch A to branch B is 6.325 miles

∵ The distance from branch B to branch C is 4 miles

∵ The half way from branch B to branch C = 1/2 × 4 = 2 miles

∴ The distance the employee may have driven before getting

   stuck in traffic = 6.325 + 2 = 8.325 miles

∴ The minimum total distance the employee may have driven

   before getting stuck in traffic is 8.3 miles

8 0
3 years ago
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