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RideAnS [48]
2 years ago
11

For the functions f(x)=5x−3 and g(x)=6x2−3, find (f∘g)(x) and (g∘f)(x)

Mathematics
1 answer:
max2010maxim [7]2 years ago
5 0

Answers:

(f \circ g)(x) = 30x^2-18\\\\(g \circ f)(x) = 150x^2-180x+51\\\\

================================================

Work Shown:

f(x) = 5x-3\\\\f(g(x)) = 5(g(x))-3\\\\(f \circ g)(x) = 5(6x^2-3)-3\\\\(f \circ g)(x) = 30x^2-15-3\\\\(f \circ g)(x) = 30x^2-18\\\\

Those steps show we start with the outer function f(x) = 5x-3. Then we replace every x with g(x) in the second step. Afterward, we plug in g(x) = 6x^2-3 and we simplify.

-----------------------

We'll follow similar steps for (g∘f)(x)

But this time we started with g(x), plug in f(x) for every x, and then simplified.

g(x) = 6x^2-3\\\\g(f(x)) = 6(f(x))^2-3\\\\(g \circ f)(x) = 6(5x-3)^2-3\\\\(g \circ f)(x) = 6(25x^2-30x+9)-3\\\\(g \circ f)(x) = 150x^2-180x+54-3\\\\(g \circ f)(x) = 150x^2-180x+51\\\\

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Answer:

<h2>The answer is option A</h2>

Step-by-step explanation:

<h3>\frac{a + bc}{wd + f}  = g</h3>

<u>First of all cross multiply</u>

That's

g( wd + f ) = a + bc

<u>Multiply the terms at the left side of the equation</u>

We have

gwd + fg = a + bc

<u>Send fg to the right side of the equation</u>

That's

gwd = a + bc - fg

<u>Divide both sides by dg to make W stand alone</u>

<h3>\frac{gwd}{dg}  =  \frac{a + bc - fg}{dg}</h3>

We have the final answer as

<h2 /><h2>w =  \frac{a + bc - fg}{dg}</h2>

Hope this helps you

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