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RideAnS [48]
2 years ago
11

For the functions f(x)=5x−3 and g(x)=6x2−3, find (f∘g)(x) and (g∘f)(x)

Mathematics
1 answer:
max2010maxim [7]2 years ago
5 0

Answers:

(f \circ g)(x) = 30x^2-18\\\\(g \circ f)(x) = 150x^2-180x+51\\\\

================================================

Work Shown:

f(x) = 5x-3\\\\f(g(x)) = 5(g(x))-3\\\\(f \circ g)(x) = 5(6x^2-3)-3\\\\(f \circ g)(x) = 30x^2-15-3\\\\(f \circ g)(x) = 30x^2-18\\\\

Those steps show we start with the outer function f(x) = 5x-3. Then we replace every x with g(x) in the second step. Afterward, we plug in g(x) = 6x^2-3 and we simplify.

-----------------------

We'll follow similar steps for (g∘f)(x)

But this time we started with g(x), plug in f(x) for every x, and then simplified.

g(x) = 6x^2-3\\\\g(f(x)) = 6(f(x))^2-3\\\\(g \circ f)(x) = 6(5x-3)^2-3\\\\(g \circ f)(x) = 6(25x^2-30x+9)-3\\\\(g \circ f)(x) = 150x^2-180x+54-3\\\\(g \circ f)(x) = 150x^2-180x+51\\\\

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Citrus2011 [14]

Given:

A triangle has side lengths of (7.8v+2.6) centimeters, (5.3v+4.5) centimeters, and (2.4w-6.7) centimeters.

To find:

The expression which represents the perimeter, in centimeters, of the triangle.

Solution:

We know that

Perimeter of a triangle = Sum of length of all sides of the triangle

Perimeter=(7.8v+2.6)+(5.3v+4.5)+(2.4w-6.7)

Now, combine like terms.

Perimeter=(7.8v+5.3v)+(2.4w)+(2.6+4.5-6.7)

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2 years ago
Help with 4 and 5 please!!
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Question 4
The magnitude;
Using Pythagoras theorem,
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                 Length = √320900
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To get the angle
Tan θ = opposite/adjacent
          = 200/530
          =  0.3774
       θ = tan^-1 (0.3774)
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The direction from the Cartesian plane is south of west.
Therefore, the magnitude and the direction will be;
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This involves adding the corresponding values.
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