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3 years ago

I really need help. And its setted up-Also I will do a 50 point giveaway

Mathematics

2 answers:

Mrac [35]3 years ago

3 0

Step-by-step explanation:

9)20/25×100%=80%

10)100/5×$136

=20×$136=$2720

zysi [14]3 years ago

3 0

Step-by-step explanation:

9. $\tt{\dfrac{20}{25}×100 }$

$\tt{\dfrac{20}{\cancel{25}}×\cancel{100} }$

$\tt{80\% }$

80% students passed in test.

10. $\tt{5\%=136\$ }$

$\tt{ 1\%=\dfrac{136}{5} }$ $

Total income=100% = $\tt{\dfrac{136}{5}×100 }$

$\tt{2720 }$ $

Total earning=2720$

You might be interested in

The probability that a certain hockey team will win any given game is 0.3773 based on their 13 year win history of 389 wins out

notsponge [240]

Answer:

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the teams wins, or they do not win. The probability of the team winning a game is independent of any other game, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3773.

This means that $p = 0.3773$

Their schedule for November contains 12 games.

This means that $n = 12$

Find the probability that the hockey team wins at least 3 games in November.

This is:

$P(X \geq 3) = 1 - P(X < 3)$

In which:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3773)^{0}.(0.6227)^{12} = 0.0034$

$P(X = 1) = C_{12,1}.(0.3773)^{1}.(0.6227)^{11} = 0.0247$

$P(X = 2) = C_{12,2}.(0.3773)^{2}.(0.6227)^{10} = 0.0824$

Then

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0034 + 0.0247 + 0.0824 = 0.1105$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1105 = 0.8895$

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

3 0

3 years ago

What is the value of t, if the value of x is 4? T - 6 = x - 6

Stella [2.4K]

Answer: T=4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the value of the numerical expression 5/8 - 5/12 (3 -1/4) + 2/3 ?

nasty-shy [4]

$\dfrac{5}{8} - \dfrac{5}{12} ( 3 - \dfrac{1}{4} )+ \dfrac{2}{3}$

$= \dfrac{5}{8} - \dfrac{5}{12} (2\dfrac{3}{4} )+ \dfrac{2}{3}$

$= \dfrac{5}{8} - \dfrac{5}{12} (\dfrac{11}{4} )+ \dfrac{2}{3}$

$= \dfrac{5}{8} - \dfrac{55}{48}+ \dfrac{2}{3}$

$= \dfrac{30}{48} - \dfrac{55}{48}+ \dfrac{32}{48}$

$= \dfrac{7}{48}$

6 0

3 years ago

Carnival T charges an entrance fee of $7.00 and $0.50 per ticket for the rides. Carnival Q charges an entree fee of $12.00 and $

FrozenT [24]

Answer:

$30

Step-by-step explanation:

Calculation for the tickets that must be purchased for Carnival T and Carnival Q to be the same

Based on the information given let x be the number of ticket to be purchased .

Carnival T entrance fee= $7.00

Ride= $0.50 per ticket

Carnival Q entree fee =12.00

Ride= $0.25 per ticket

Tickets=$7.00 + ($0.50* x) = $12.00 + ($0.25* x)

.25 x = 5.00

Hence:

x=$.25+$5.00

×=$30

Therefore the amount of tickets that must be purchased in order for the total cost at Carnival T and Carnival Q to be the same will be $30

3 0

3 years ago

Write an equation of the line below.

Dafna11 [192]

Answer:

$\large\boxed{y=4x+3}$

Step-by-step explanation:

The slope-intercept form of an equation of aline:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfraxc{y_2-y_1}{x_2-x_1}$

From the graph we have the points:

(-2, -5)

y-intercept (0, 3) → b = 3

Calculate the slope:

$m=\dfrac{3-(-5)}{0-(-2)}=\dfrac{8}{2}=4$

Put the value of the slope and the y-intercept to the equation of a line:

$y=4x+3$

3 0

3 years ago