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USPshnik [31]
2 years ago
10

jennifer works at whataburger and earned 168.75 last week. If she worked 22.5 hours, how much does she earn per hour?

Mathematics
2 answers:
Juli2301 [7.4K]2 years ago
6 0

Answer:

7.5

Step-by-step explanation:

168.75 divided by 22.5 = 7.5

$7.50 dollars an hour.

7.50 x 22.5 = 168.75

il63 [147K]2 years ago
6 0
7.5 168.75/22.5 =7.5 an hour
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White raven [17]

Answer:

A is the only solution.

Step-by-step explanation:

A simple way to solve it is to plug in the x and y values

For A, we plug in 2 for x and 3 for y

3-3=5(2-2)

0=5(0)

0=0

Ordered pair A is a solution

For B, plug in 3 for x and 2 for y

2-3=5(3-2)

-1=5(1)

-1 does not equal 5

Therefore only A is a solution

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3 years ago
If 2p + p = 20 then what is 2p - 5 =
Wewaii [24]
Ok first we have to find out whats 2p+p=20 combine like terms to get 3p=20 the divide 3 on each side to get p=6 2/3 then we plug in 6 2/3 to 2p-5 so 2(6 2/3) -5 so its 12.666-5 to get 7.666 so that's the answer.
4 0
2 years ago
An archer hits a bullseye 64% of the time. What is the probability the archer hits
Brums [2.3K]

Answer:

C. 0.077

Step-by-step explanation:

Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

n = 10, r = 4, p = 0.64, q = 0.36.

P = ₁₀C₄ (0.64)⁴ (0.36)⁶

P = 210 (0.64)⁴ (0.36)⁶

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6 0
3 years ago
What is the zero of function f?f(x)=3 square root of x+3 -6
grin007 [14]

Solution:

Given:

f(x)=3\sqrt{x+3}-6

The zeros of a function are the values of x when f(x) is equal to 0.

Hence,

\begin{gathered} 0=3\sqrt{x+3}-6 \\  \\ Collecting\text{ the like terms,} \\ 0+6=3\sqrt{x+3} \\ 6=3\sqrt{x+3} \\  \\ Divide\text{ both sides by 3;} \\ \frac{6}{3}=\sqrt{x+3} \\ 2=\sqrt{x+3} \\  \\ Taking\text{ the square of both sides;} \\ 2^2=x+3 \\ 4=x+3 \\  \\ Collecting\text{ the like terms;} \\ 4-3=x \\ 1=x \\ x=1 \end{gathered}

Therefore, x = 1

The correct answer is OPTION A.

3 0
1 year ago
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muminat

Answer:

13A

Step-by-step explanation:

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